this is similar to conversion of no in base 26.( where digits are
a,b,c,d...z) just think it like decimal to binary conversion here base is
instead 26.
char Carr[26]={a,b,c...z}
i=0;
int arr[];
do
{
arrr[i++]=n%26;
n/=2;
}
while(n) ;
for(int i=n-1;i>=0;i--)
cout<<Carr[a[i]];
correct me if i am wrong.
On Wednesday, 8 August 2012 12:56:56 UTC+5:30, ashgoel wrote:
>
> Imagine a sequence like this: a, b, c...z, aa, ab, ac...zz, aaa, aab,
> aac.... aax, aaz, aba, abc... (Its same as excel column names). Given an
> integer (n), generate n-th string from the above sequence.
>
> Best Regards
> Ashish Goel
> "Think positive and find fuel in failure"
> +919985813081
> +919966006652
>
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