well we can do with just one array. Overwrite the answer directly on left[]
array.

On Thu, Aug 16, 2012 at 6:47 PM, mohit <mohitsingh1...@gmail.com> wrote:

>
> here are the steps :
> 1) Construct a temporary array left[] such that left[i] contains product
> of all elements on left of A[i] excluding A[i].
> 2) Construct another temporary array right[] such that right[i] contains
> product of all elements on on right of A[i] excluding A[i].
> 3) To get OUT[], multiply left[] and right[].
>
> time complexity : O(n)
>
>
> On Thursday, August 16, 2012 2:26:58 PM UTC+5:30, ram wrote:
>>
>>
>> Hi,
>>
>>        This is a microsoft question asked in our campus previous year. 
>> Anyone having idea please share it here...
>>
>>        Given an array of n elements A[n]. Write a program to create a new 
>> array OUT[n],
>>
>>         which has its elements as multiplication of all the elements in the 
>> input array A[n] except that element (i.e.) OUT[2] = A[0] * A[1] * A[3] * ? 
>> * A[n-1].
>>          Constraint is one should not use division operator.
>>
>>  --
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