@ashish : i.e in decreasing order inorder(root) if not null inorder(root->right); inorder(root->left);
On Mon, Sep 3, 2012 at 4:35 PM, Rahul Kumar Patle <patlerahulku...@gmail.com > wrote: > @dave same doubt as @atul, how we can manage both function parallel > and to all can we traverse a tree using some looping instead of > traditional recursive methods..?? > > On Mon, Sep 3, 2012 at 1:13 PM, atul anand <atul.87fri...@gmail.com>wrote: > >> @Dave : algo seems fine...but it seems to me that it would difficult to >> maintain both left to right and right to left parallel way :( :( . >> it would be gr8 if you can provided little bit of coded algorithm for it. >> >> >> On Mon, Sep 3, 2012 at 10:36 AM, Dave <dave_and_da...@juno.com> wrote: >> >>> @Atul007: No need to destroy the BST. Perform two simultaneous inorder >>> traversals of the BST, one from left to right (the usual direction) and one >>> from right to left. At any stage you have selected two nodes. If the sum is >>> less than the given number, advance the left-to-right traversal; If the sum >>> is greater, advance the right-to-left traversal. Quit with success when the >>> sum equals the given number or with failure when the two traversals have >>> reached the same node. >>> Dave >>> >>> On Sunday, September 2, 2012 11:00:42 PM UTC-5, atul007 wrote: >>> >>>> convert BST to sorted DLL.. >>>> now it is a double linked list , so we can find 2 number in O(n) time >>>> by keeping 2 pointers(one at start and one at end) from sorted DLL. >>>> now convert DLL to BST. >>>> >>>> On Mon, Sep 3, 2012 at 1:32 AM, Navin Kumar <algorit...@gmail.com>wrote: >>>> MICROSOFT:Given a BST and a number. Find two node in a BST whose sum is >>>> equal to given number in O(n) time and O(1) space. >>>> >>>> -- >>> You received this message because you are subscribed to the Google >>> Groups "Algorithm Geeks" group. >>> To view this discussion on the web visit >>> https://groups.google.com/d/msg/algogeeks/-/oizd-5CSfuoJ. >>> >>> To post to this group, send email to algogeeks@googlegroups.com. >>> To unsubscribe from this group, send email to >>> algogeeks+unsubscr...@googlegroups.com. >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > Thanks and Regards: > Rahul Kumar > Patle<http://www.linkedin.com/profile/view?id=106245716&trk=tab_pro> > M.Tech, School of Information Technology > Indian Institute of Technology, Kharagpur-721302, > India<http://www.iitkgp.ac.in/> > Mobile No: +91-8798049298, +91-9424738542 > Alternate Email: rahulkumarpa...@hotmail.com > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.