@ashish : i.e in decreasing order

inorder(root)
   if not null
         inorder(root->right);
         inorder(root->left);

On Mon, Sep 3, 2012 at 4:35 PM, Rahul Kumar Patle <patlerahulku...@gmail.com
> wrote:

> @dave same doubt as @atul, how we can manage both function parallel
> and to all can we traverse a tree using some looping instead of
> traditional recursive methods..??
>
> On Mon, Sep 3, 2012 at 1:13 PM, atul anand <atul.87fri...@gmail.com>wrote:
>
>> @Dave : algo seems fine...but it seems to me that it would difficult to
>> maintain both left to right and right to left parallel way :( :( .
>> it would be gr8 if you can provided little bit of coded algorithm for it.
>>
>>
>> On Mon, Sep 3, 2012 at 10:36 AM, Dave <dave_and_da...@juno.com> wrote:
>>
>>> @Atul007: No need to destroy the BST. Perform two simultaneous inorder
>>> traversals of the BST, one from left to right (the usual direction) and one
>>> from right to left. At any stage you have selected two nodes. If the sum is
>>> less than the given number, advance the left-to-right traversal; If the sum
>>> is greater, advance the right-to-left traversal. Quit with success when the
>>> sum equals the given number or with failure when the two traversals have
>>> reached the same node.
>>> Dave
>>>
>>> On Sunday, September 2, 2012 11:00:42 PM UTC-5, atul007 wrote:
>>>
>>>> convert BST to sorted DLL..
>>>> now it is a double linked list , so we can find 2 number in O(n)  time
>>>> by keeping 2 pointers(one at start and one at end) from sorted DLL.
>>>> now convert DLL to BST.
>>>>
>>>>  On Mon, Sep 3, 2012 at 1:32 AM, Navin Kumar <algorit...@gmail.com>wrote:
>>>> MICROSOFT:Given a BST and a number. Find two node in a BST whose sum is
>>>> equal to given number in O(n) time and O(1) space.
>>>>
>>>>  --
>>> You received this message because you are subscribed to the Google
>>> Groups "Algorithm Geeks" group.
>>> To view this discussion on the web visit
>>> https://groups.google.com/d/msg/algogeeks/-/oizd-5CSfuoJ.
>>>
>>> To post to this group, send email to algogeeks@googlegroups.com.
>>> To unsubscribe from this group, send email to
>>> algogeeks+unsubscr...@googlegroups.com.
>>> For more options, visit this group at
>>> http://groups.google.com/group/algogeeks?hl=en.
>>>
>>
>>  --
>> You received this message because you are subscribed to the Google Groups
>> "Algorithm Geeks" group.
>> To post to this group, send email to algogeeks@googlegroups.com.
>> To unsubscribe from this group, send email to
>> algogeeks+unsubscr...@googlegroups.com.
>> For more options, visit this group at
>> http://groups.google.com/group/algogeeks?hl=en.
>>
>
>
>
> --
> Thanks and Regards:
> Rahul Kumar 
> Patle<http://www.linkedin.com/profile/view?id=106245716&trk=tab_pro>
> M.Tech, School of Information Technology
> Indian Institute of Technology, Kharagpur-721302, 
> India<http://www.iitkgp.ac.in/>
> Mobile No: +91-8798049298, +91-9424738542
> Alternate Email: rahulkumarpa...@hotmail.com
>
>  --
> You received this message because you are subscribed to the Google Groups
> "Algorithm Geeks" group.
> To post to this group, send email to algogeeks@googlegroups.com.
> To unsubscribe from this group, send email to
> algogeeks+unsubscr...@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/algogeeks?hl=en.
>

-- 
You received this message because you are subscribed to the Google Groups 
"Algorithm Geeks" group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.

Reply via email to