@tendua: Answer will be 6C3 x 3! . For example: If 5 letters are given then you can get only 10 combination of different letter = 5C3
ABC ABD ABE BCD BCE CDE ACD ACE ADE BDE now each of these can be arranged in 3! ways. So final answer will be : 120 On Fri, Sep 7, 2012 at 1:11 AM, tendua <bharat.kra...@gmail.com> wrote: > > http://placement.freshersworld.com/placement-papers/Persistent-/Placement-Paper-Whole-Testpaper-1884 > question no. 4 in 5th section > > > On Thursday, September 6, 2012 4:40:08 PM UTC+5:30, isandeep wrote: > >> Can you send the link to the question. >> >> On Thu, Sep 6, 2012 at 4:35 PM, tendua <bharat...@gmail.com> wrote: >> >>> from the six elements, we could choose any three in C(6,3) ways which is >>> 20 and then permute all the three elements so it will be multiplied by 3! >>> which is 6. Hence, 20*6 = 120. We still have to multiply it by 3 to get 360 >>> but I'm not getting why? >>> >>> >>> On Thursday, September 6, 2012 3:54:11 PM UTC+5:30, atul007 wrote: >>> >>>> seems output should be 20. >>>> >>>> On Thu, Sep 6, 2012 at 3:26 PM, tendua <bharat...@gmail.com> wrote: >>>> >>>>> from the set {a,b,c,d,e,f} find number of arrangements for 3 alphabets >>>>> with no data repeated? >>>>> Answer given is 360. but how? >>>>> >>>>> -- >>>>> You received this message because you are subscribed to the Google >>>>> Groups "Algorithm Geeks" group. >>>>> To view this discussion on the web visit https://groups.google.com/d/* >>>>> *ms**g/algogeeks/-/E4U2XlfkvgMJ<https://groups.google.com/d/msg/algogeeks/-/E4U2XlfkvgMJ> >>>>> . >>>>> To post to this group, send email to algo...@googlegroups.com. >>>>> To unsubscribe from this group, send email to algogeeks+...@** >>>>> googlegroups.com**. >>>>> >>>>> For more options, visit this group at http://groups.google.com/**group >>>>> **/algogeeks?hl=en <http://groups.google.com/group/algogeeks?hl=en>. >>>>> >>>> >>>> -- >>> You received this message because you are subscribed to the Google >>> Groups "Algorithm Geeks" group. >>> To view this discussion on the web visit https://groups.google.com/d/** >>> msg/algogeeks/-/VMO1othQRcQJ<https://groups.google.com/d/msg/algogeeks/-/VMO1othQRcQJ> >>> . >>> >>> To post to this group, send email to algo...@googlegroups.com. >>> To unsubscribe from this group, send email to algogeeks+...@** >>> googlegroups.com. >>> For more options, visit this group at http://groups.google.com/** >>> group/algogeeks?hl=en <http://groups.google.com/group/algogeeks?hl=en>. >>> >> >> -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To view this discussion on the web visit > https://groups.google.com/d/msg/algogeeks/-/z6KbH2i6BP0J. > > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
