don't calculate it till e*10^6..calculating it till 10000 would suffice .

On Thu, Sep 27, 2012 at 9:03 AM, Wladimir Tavares <wladimir...@gmail.com>wrote:

> http://www.spoj.pl/problems/FACVSPOW/
>
> Hi guys,
> I'm trying to solve this problem but I'm getting TLE.
> Basically, the problem wants to know when n! > (a ^ n) for a given (a <=
> 1000 000).
>
> My basic idea was to pre-calculate all values ​​n! for n <= e * 1000000
> using log.
>
> Then use binary search in the range [2 * a, (e * a)] to discover when n! >
> a ^ n
>
> Anyone have any ideas?
>
>
> Wladimir Araujo Tavares
> *Federal University of Ceará <http://lia.ufc.br/%7Ewladimir/>
> Homepage <http://lia.ufc.br/%7Ewladimir/> | 
> Maratona<https://sites.google.com/site/quixadamaratona/>|
> *
>
>
>
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-- 
--
Thanks
Rahul Singh
B.tech CSE ,final Year
IIT Roorkee

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