ossam link...thnx..vikram

On Tue, Oct 30, 2012 at 3:20 PM, Vikram Pradhan <vpradha...@gmail.com>wrote:

> Macro arguments are scanned and expanded before the substitution in macro
> body unless they are convert to a string representation (using #) or
> concatenated with other tokens (using ##).
>
> Xstr(oper)  => Xstr(multiply) =>str(multiply)=>"multiply"    // in
> Xstr(x) , x is a simple argument so it will expand fully
>
> str(oper)    =>"oper"    // in str(x) , x is converting to string so it
> will not get expanded
>
> check this link :
> http://gcc.gnu.org/onlinedocs/cpp/Argument-Prescan.html#Argument-Prescan
>
>
>
>
> On Sun, Oct 28, 2012 at 3:28 PM, rahul sharma <rahul23111...@gmail.com>wrote:
>
>> And when char *opername=str(oper);
>>
>> then o/p is oper....why behaviour is diff. in 2 cases
>>
>> On Sun, Oct 28, 2012 at 2:53 PM, rahul sharma <rahul23111...@gmail.com>wrote:
>>
>>> #include<stdio.h>
>>> #include str(x) #x
>>> #define Xstr(x) str(x)
>>> #define oper multiply
>>>
>>>
>>> int main()
>>> {
>>> char *opername=Xstr(oper);
>>> printf("%s",opername);
>>> }
>>> so firstly     Xstr is expanded to str(oper)
>>> then str(oper) is expanded to #oper now i have read that
>>>
>>> If, however, a parameter name is preceded by a # in the replacement
>>> text, the
>>> combination will be expanded into a quoted string with the parameter
>>> replaced by the actual argument...and in this case actual is also oper so
>>> it becomes "oper"...so it should print oper .....i thnik i am mistaken
>>> anyhre...correct???
>>>
>>
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>
>
>
> --
> Vikram Pradhan | B.Tech| Computer Science & Engineering | NIT Jalandhar  |
>  9740186063 |
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