Thats because you have swapped pointers and printing variables.
On Mon, Oct 29, 2012 at 11:22 PM, rahul sharma <rahul23111...@gmail.com>wrote:
> I have taken form book...i am writing exact code
>
> #include<stdio.h>
> #define swap(a,b,c) c t;t=a,a=b,b=t;
>
>
> int main()
> {
> float a,x;
> a=20.0;
> x=30.0;
> float *p,*q;
> p=&a,q=&x;
> swap(p,q,float*);
> printf("%f %f",a,x);
> getchar();
> }
>
> o/p=20.000 30.000
>
>
> why not swapped???
> On Mon, Oct 29, 2012 at 11:01 PM, atul anand <atul.87fri...@gmail.com>wrote:
>
>> if you think the your expanded version is incorrect.You are wrong ,
>> because int * will hold pointer but you are not allocating address of
>> x ..instead you are allocating x value as an address of x to *t.This
>> wont work.
>> so to make it work you need to save the address of x and y in temp
>> pointers i.e
>>
>> int *p.*q;
>> p=&x;
>> q=&y;
>> int t;
>> t=*p;
>> *p=*q;
>> *q=t;
>> now you can convert it into macro.
>>
>> On 10/29/12, rahul sharma <rahul23111...@gmail.com> wrote:
>> > @atul...mistakenly i have put w at place of t in my last post...i wana
>> say
>> >
>> >
>> >
>> > On Mon, Oct 29, 2012 at 10:07 AM, dCoder <bansal....@gmail.com> wrote:
>> >
>> >> Just replace your macro with its definition and you will understand.
>> >>
>> >> its not doing swapping of pointers...plz explain
>> >>
>> >
>> >
>> > @dCode i expanded..but its fine...please tell
>> >
>> >> #include<stdio.h>
>> >> #define swap(a,b,c) c t;t=a,a=b,b=t
>> >>
>> >> int main
>> >> int x=10,y=20;
>> >> int *p,*q;
>> >> swap(x,y,int*);
>> >>
>> > int * t;
>> > t=x;
>> > x=y;
>> > y=t;
>> >
>> >
>> > There is int* at the end..there is som problem with my
>> > keyborad...:(.........acc to me axpanded version is above..but not
>> swapping
>> > two pointerss....plz comment
>> >
>> >
>> >
>> >
>> >> On Sun, Oct 28, 2012 at 9:16 PM, rahul sharma
>> >> <rahul23111...@gmail.com>wrote:
>> >>
>> >>> its now doing swapping of pointers...plz explain
>> >>>
>> >>>
>> >>> On Sun, Oct 28, 2012 at 8:08 PM, atul anand
>> >>> <atul.87fri...@gmail.com>wrote:
>> >>>
>> >>>> it should swap....
>> >>>>
>> >>>> On 10/28/12, rahul sharma <rahul23111...@gmail.com> wrote:
>> >>>> > Why the following code is not able to swap two macros???although it
>> >>>> > is
>> >>>> > easily swapping 2 variables
>> >>>> >
>> >>>> > #include<stdio.h>
>> >>>> > #define swap(a,b,c) c t;t=a,a=b,b=t
>> >>>> >
>> >>>> >
>> >>>> > int main
>> >>>> >
>> >>>> >
>> >>>> > int x=10,y=20;
>> >>>> > int *p,*q;
>> >>>> >
>> >>>> > swap(x,y,int);
>> >>>> >
>> >>>> > --
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