Yes it will print 30+ times. fork() --> it's create the the child process which copie's the address stack of the parent process. now when you will do fork(); look 1st iteration --> it wil break; ( if parent process scheduled 1st by the kernel ) when 2nd iteration --> it will again fork in child process. and will print hello once and dan goes to parent dan break. when 3rd iteration --> it will fork again and print hello twice and dan break when 4th iteration --> it will again fork and prnt hello 4 times i.e. hello once by iteration and dan fork child will start process from start and dan print hello 3 more times and dan parent will schedule and dan break. and so on...
On 31 October 2012 11:49, tendua <bharat.kra...@gmail.com> wrote: > \n also flushes the standard output buffer. If it is not present, it is > possible that you have previously entered data in it. Flushing also means > it forces printf to print on the screen as soon as \n is processed. > Otherwise it is buffered output and you can never predict how long would OS > buffer your output and when precisely it chooses to actually print. > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To view this discussion on the web visit > https://groups.google.com/d/msg/algogeeks/-/cNFex4s9a8UJ. > > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
