@vishwa : that is not correct. Check : http://ideone.com/Kn7hRn
On Wed, Nov 7, 2012 at 9:20 PM, vishwa <vishwavam...@gmail.com> wrote:
> I guess its other way.
>
> According you guys explanation after evaluating the expression first the
> if condition turns out to be if(1);
>
> And the program runs infinitely..
>
> first -- ++k <= 8 --- turns true and k becomes 6.
>
> second -- k++ / 5 --- skipped. k remains 6
>
> third -- ++k < 5 --- turns false and k becomes 7.
>
>
> Hope its very clear
>
>
>
>
> On Wed, Nov 7, 2012 at 7:13 AM, apsalar <kavya...@gmail.com> wrote:
>
>> We start with k = 5.
>>
>> if ++k < 5 translates to if 6 < 5 => which is false.
>> No need to evaluate k++/5 (short-circuiting)
>> if ++k <= 8 translates to (6+1) 7 <= 8 which is true.
>> So, 7 gets printed.
>>
>>
>> On Tuesday, November 6, 2012 6:22:13 AM UTC-5, Anil Sharma wrote:
>>>
>>> main()
>>> {
>>> int k = 5;
>>> if (++k < 5 && k++/5 || ++k <= 8);
>>> printf("%d ", k);
>>> }
>>>
>>> the output shud be 8 but it comes out to be 7.why???
>>> as increment operator has higher precedence among them so increment shud
>>> be done throughout at first and after then other operators shud be
>>> evaluated.so output shud be 8.
>>>
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>
>
>
> --
> *Thanks & Regards,*
> *Vishwa*
> *+91 9964051504*
>
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--
Aamir Khan | 4th Year | Computer Science & Engineering | IIT Roorkee
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