I am afraid both of you are incorrect..
1. since the code modified by you will compile but give sigsegv anyway.
2. The statement " *p = 0; " has nothing to do with the " random address"
you are talking about.
On Mon, Dec 17, 2012 at 7:25 PM, Prakhar Jain <jprakha...@gmail.com> wrote:
> You are initialising random memory address with 0, which OS doesn't allow.
>
> On 12/17/12, Shubham Sandeep <s.shubhamsand...@gmail.com> wrote:
> > how does this code achieve SIGSEGV????
> > code:
> > *p;main(){*p=0;}
> >
> > --
> > Regards,
> > SHUBHAM SANDEEP
> > IT 3rd yr.
> > NIT ALD.
> >
> > --
> >
> >
> >
>
>
> --
> --
> Prakhar Jain
> IIIT Allahabad
> B.Tech IT 4th Year
> Mob no: +91 9454992196
> E-mail: rit2009...@iiita.ac.in
> jprakha...@gmail.com
>
> --
>
>
>
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- Saurabh Paliwal
B-Tech. Comp. Science and Engg.
IIT ROORKEE
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