yes the below logic is correct 1-> 1st(1) 2-> 1st(2) 3-> 2nd(1,2 or 2,1) 4-> 1st (1,2,1 or 1,1,2) 5->1st(2, 1, 2 or 2, 2, 1) 6-> 2nd(2, 1, 3) or 1, 2,3)) 2nd will win 7-> 1st(1, 1, 2, 3 or 1, 2, 1,3 or .,. 8-> 1st (2, 1, 2, 3 or 2, 2,1, 3 or ..
In above 3 can be (1,2) or (2,1) Thanks Kumar Anurag On Sat, Jan 12, 2013 at 10:11 PM, Lucifer <sourabhd2...@gmail.com> wrote: > > @siva.. > > if (n%3 == 0) > "Player 1 will lose" > else > "Player 1 will win. The no. of balls picked in the first turn will > be n%3" > > -- > > > -- Kumar Anurag --
