@sourabh : how do u find whether the element in stream gets repeated in
heap.--> O(n) time...totally its O(nk) algo ..

If we maintain max-heap with BST property on index, then it would be
O(nlogk).

On Wed, Feb 6, 2013 at 12:25 PM, sourabh jain <wsour...@gmail.com> wrote:

> for 2nd question you can make a heap with their index as a factor to
> heapify them. whenever a integer in stream gets repeated you just nead to
> remove it from heap and heapify it.
>
>
> On Wed, Feb 6, 2013 at 10:00 AM, navneet singh gaur <
> navneet.singhg...@gmail.com> wrote:
>
>> nice algo ankit, so it will be nlogn using O (n) space only. What abt
>> 2nd Q., which have a big online stream.
>>
>> On Mon, Feb 4, 2013 at 9:30 PM, kumar ankit <k.anki...@gmail.com> wrote:
>> > For 1:
>> > i think you can use sorting, sort the array and keep the indices of the
>> > numbers in the sorted list.
>> > Now traverse the sorted list and  in the sorted list you need to find
>> the
>> > unique number with the
>> > minimum index which is easy to find.
>> >
>> > Eg: Array:    5 3 1 2 4 1 4
>> >       Indices: 0 1 2 3 4 5 6
>> >
>> >
>> > After sorting : Array:    1 1 2 3 4 4 5
>> >                     Indices:  2 5 3 1 4 6 1
>> >
>> > Now you can see the unique number with lowest index is 3(index=1). So ,
>> you
>> > have your answer.
>> >
>> >
>> > On Mon, Feb 4, 2013 at 3:45 PM, navneet singh gaur
>> > <navneet.singhg...@gmail.com> wrote:
>> >>
>> >> 1. Given a array,find a first unique integer.
>> >> 2. Integers are coming as online stream,have to find a kth unique
>> integer
>> >> till now.
>> >>
>> >> For 1.
>> >>
>> >> Even we cannot use sorting for solving this as if we sort it than our
>> >> first number which is non-repetitive changes.
>> >>
>> >> The best I am able to do is nlogn using a space of O( n ).
>> >>
>> >> For 2. No idea
>> >>
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>> >
>> >
>> >
>> >
>> > --
>> > Kumar Ankit
>> > Senior Undergraduate
>> > Department of Computer Engineering
>> > Institute of Technology
>> > Banaras Hindu University
>> > Varanasi
>> > Ph: +91 9473629892
>> >
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>>
>>
>> --
>> navneet singh gaur
>>
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>
>
> --
> Regards,
> Sourabh Kumar Jain
> +91-8971547841
>
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