Don, I'm trying to get all the words from trie iteratively, because I'm
creating trie of whole dictionary (more than 200k words) and searching
recursively will consume a lot of stack space.
Thanks for your help!
On Wed, May 29, 2013 at 9:44 AM, rahul sharma <rahul23111...@gmail.com>wrote:
>
> @don u r searching in a previously built trie with the given filter...then
> wat is this add fxn doing?correct me if m getting u wrng
>
> On Wednesday, May 29, 2013, avinesh saini <avinesh.sa...@gmail.com> wrote:
> > Thank you Don, I was also trying in similar way. But here I'm confused
> how you are storing the traversed words. Are you adding whole words at the
> node on which word is ending during insertion.
> >
> >
> > On Wed, May 29, 2013 at 12:36 AM, Don <dondod...@gmail.com> wrote:
> >>
> >> void findWords(trie *root, char *filter)
> >> {
> >> if (!root) return;
> >>
> >> if (*filter == 0) // When you reach the end of the filter at the
> >> end of a valid word, add the word.
> >> {
> >> if (root->words) words.add(root->word);
> >> }
> >> else if (*filter == '.') // Search for words with any letter
> >> {
> >> for(int i = 'a'; i <= 'z' ; ++i)
> >> findWords(root->link[i], filter+1);
> >> }
> >> else // Search for words with the required letter
> >> {
> >> findWords(root->link[*filter], filter+1);
> >> }
> >> }
> >>
> >> On May 28, 4:47 am, avinesh saini <avinesh.sa...@gmail.com> wrote:
> >> > How to search all the matching words for a filter in a trie.
> >> > e.g.
> >> > searching by filter "...r..m" will find all the words(of length = 7)
> in
> >> > trie in which 4th character is 'r' and 7th character is 'm'.
> >> >
> >> > --
> >> > *
> >> > *
> >> > *thanks & regards,*
> >> > *Avinesh
> >> > *
> >>
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> >>
> >
> >
> >
> > --
> >
> > thanks & regards,
> > Avinesh
> >
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*
*
*regards,*
*Avinesh Kumar
National Institute of Technology, Calicut.*
*Kerala- 673601*
*+91 7849080702*
*http://www.facebook.com/avinesh.saini*
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