This will help u i guess :

#include <iostream>
#include <string.h>
using namespace std;

void swap(char str[],int m,int n ) {
char temp=str[m];
str[m]=str[n];
str[n]=temp;
}
bool duplicate(char str[], int start, int end)
{   if(start == end)
      return false;
    else
      for(; start<end; start++)
        if (str[start] == str[end])
          return true;
  return false;
}
void Permute(char str[], int start, int end)
{
    if(start >= end){
      cout<<str<<endl;
      return;
    }
    for(int i=start;i<=end;i++)
    {  if(!duplicate(str,start,i))
       {
        swap(str,start,i);
        Permute(str,start+1,end);
        swap(str,start,i);
       }
    }
}

int main()
{
  char Str[]="aba";
  Permute(Str,0,strlen(Str)-1);
   return 0;
}



NIshant Pandey
Cell : 9911258345
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On Tue, Jan 7, 2014 at 4:44 PM, kumar raja <rajkumar.cs...@gmail.com> wrote:

> This u can do it using the backtracking method. To know how to use
> backtracking refer algorithm design manual by steve skiena.
>
>
> On 7 January 2014 03:35, bujji jajala <jajalabu...@gmail.com> wrote:
>
>> generate all possible DISTINCT permutations of a given string with some
>> possible repeated characters. Use as minimal memory as possible.
>>
>> if given string contains n characters in total with m < n distinct
>> characters each occuring n_1, n_2, ....n_m times where n_1 + n_2 + ...+ n_m
>> = n
>>
>> program should generate n! / ( n_1! * n_2! * ....* n_m!  )  strings.
>>
>> Ex:
>>  aba  is given string
>>
>> Output:
>>
>> aab
>> aba
>> baa
>>
>>
>> -Thanks,
>> Bujji
>>
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