i din't get ur question. isn't the equation "*(x - 7) + 7 = (x + 1) - 5*" invalid ?
-- Thanks and Regards, Amol Sharma On Wed, Jan 15, 2014 at 3:34 AM, Arpit Sood <soodfi...@gmail.com> wrote: > Equivalent to solving an infix expression using stack with a pair (first > variable, second constant) as the element > > > On Sat, Jan 11, 2014 at 6:50 AM, atul anand <atul.87fri...@gmail.com>wrote: > >> Hello, >> >> How to solve an equation with one unknown variable ? >> operator allowed are : + , - >> >> for eg . input could be :- >> x + ( 5 + 4 ) = 6 >> (x - 7) + 7 = (x + 1) - 5 >> >> If operator also allows " * " (multiply) , then what change in algorithm >> is required. >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To unsubscribe from this group and stop receiving emails from it, send an >> email to algogeeks+unsubscr...@googlegroups.com. >> > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to algogeeks+unsubscr...@googlegroups.com. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To unsubscribe from this group and stop receiving emails from it, send an email to algogeeks+unsubscr...@googlegroups.com.
