Just think in this manner that put 0 star in front, then 1 star in front
and so on and while doing this just compare both the strings. If you are
not able to understand just tell me I will mail my code to you.

Prateek Khandelwal
Software Engineer in Directi
+91-7042393719

On Tue, Oct 7, 2014 at 11:23 PM, Prateek Khandelwal <pratv...@gmail.com>
wrote:

> I think this question can be done in O((m-n)*n) where m is the length of
> larger string and n is the length of smaller string
>
> Prateek Khandelwal
> Software Engineer in Directi
> +91-7042393719
>
> On Tue, Oct 7, 2014 at 6:06 PM, vikas <vikas.rastogi2...@gmail.com> wrote:
>
>> question unclear ?What is to be minimize ?
>> in given example:
>> ca*d*bch
>> abc
>>
>> what is role of "d" ?
>>
>>
>> On Monday, 6 October 2014 22:52:10 UTC+5:30, Rishav wrote:
>>>
>>> Hi everyone,
>>>
>>> I was asked this question recently in an interview: Given two strings of
>>> unequal length, you have to pad the smaller string (either at the beginning
>>> or the end or both, no insertions allowed) with any character you want. The
>>> idea is to minimize the index-wise non-similar elements in both the strings.
>>>
>>> Example:
>>> abc
>>> cadbch
>>>
>>> The character we want should be:
>>>
>>> **abc*, such that the difference is just one(b and c are same for both
>>> strings in this position). I only found a solution with O(mn) complexity.
>>> Anybody can suggest any optimizations?
>>>
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>

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