Hi Puneet,
First of all you have to do the type convertion for the below
struct bst *start=malloc(sizeof(struct bst));
as
struct bst *start= (struct bst *)malloc(sizeof(struct bst));
Reason behind is malloc will return void pointer.
Try to run after making this change at all the places where you are
calling malloc.
Regards,
Shravan
On Fri, Sep 4, 2015 at 9:47 AM, Puneet Gautam <puneet.nsi...@gmail.com> wrote:
> HI, I am running the following peice of code on Dev-cpp compiler
>
> #include<stdio.h>
> #include<stdlib.h>
> #include<stddef.h>
> struct bst
> {
> int info;
> struct bst *leftnode;
> struct bst *rightnode;
> };
> void insert(struct bst *node,int val1)
> {
> struct bst *newnode=malloc(sizeof(struct bst));
> struct bst *temp=malloc(sizeof(struct bst));
> newnode->info=val1;
> temp=node;
> while(temp)
> { printf("\n Inside while loop");
> if(val1<=temp->info)
> if(temp->leftnode!=NULL)
> { temp=temp->leftnode;
> printf("\n IN if of left");
> }
> else
> break;
> else
> if((temp->rightnode)!=NULL)
> { temp=temp->rightnode;
> printf("\n IN if of right");
> }
> else
> break;
> }
> if(!temp)
> { free(temp);
> return;
> }
> else if(val1<=temp->info)
> { temp->leftnode=newnode;
> printf("\n Inserted to the left");
> }
> else
> { temp->rightnode=newnode;
> printf("\n Inserted to the right");
> }
> newnode->leftnode=NULL;
> newnode->rightnode=NULL;
> free(temp);
> }
> int main()
> {
> struct bst *start=malloc(sizeof(struct bst));
> // struct bst *newnode=malloc(sizeof(struct bst));
> start->info=10;
> start->leftnode=NULL;
> start->rightnode=NULL;
> printf("Data is :%d",start->info);
> getchar();
> insert(start,20);
> insert(start,5);
> getchar();
> free(start);
> return 0;
> }
>
> The compiler reports Access violation at the highlighted lines i.e.
> insert(start,5);
> But at the run of insert(start,20); , there is no problem as such.
> Please help !!
>
> Regards
> Puneet
>
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Thanks & Regards,
Shravan Kumar Chiluveri
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