To comment on the following update, log in, then open the issue:
http://www.openoffice.org/issues/show_bug.cgi?id=58181


User simonbr changed the following:

                  What    |Old value                 |New value
================================================================================
                   Summary|error making              |error making
                          |bf_sch680mi.dll           |bf_sch680mi.dll
--------------------------------------------------------------------------------




------- Additional comments from [EMAIL PROTECTED] Sun Nov 20 03:10:47 -0800 
2005 -------
Trying to find the cause of the problem, I got as far as tools/inc/stream.hxx
(solver/inc/tools/stream.hxx) which contains the lines:

#ifdef ENABLE_BYTESTRING_STREAM_OPERATORS
        SvStream&               operator<<( const ByteString& rString ) { 
return WriteByteString(
rString ); }
#endif
#ifdef ENABLE_STRING_STREAM_OPERATORS
        SvStream&               operator<<( const UniString& rString ) { return
WriteByteString(rString); }
#endif

(of which the second line is compiled in
binfilter/bf_sch/source/core/sch_sctmode2.cxx). 
Because it is an inline definition, at first sight it looks like the same
problem as in issue 57951 but I think it's something else, as the "automation"
project was built successfully using the new cl.exe and link.exe.

I tried the following things: 
- added a dummy function that calls WriteByteString in sch_sctmode2.cxx. But
then I get this error:

c:\ooo-20\binfilter\bf_sch\source\core\sch_chtmode2.cxx(989) : error C3861: 'Wri
teByteString': identifier not found, even with argument-dependent lookup

which I don't understand, because WriteByteString is declared in stream.hxx
which appears to be included. 

- split the declaration and the inline definition of the operators, but then I
get this error: 

c:\ooo-20\solver\680\wntmsci10.pro\inc\tools\stream.hxx(736) : error C2805: bina
ry 'operator >>' has too few parameters

which I don't understand either. Why does the compiler think it's a binary 
operator?



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