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http://www.openoffice.org/issues/show_bug.cgi?id=44793





------- Additional comments from [EMAIL PROTECTED] Thu Dec  8 22:45:37 -0800 
2005 -------
---- from langdev mailing list ----
Hi Laurent,

Quoting Laurent Godard <[EMAIL PROTECTED]>:

> Hi all, Hi nemeth
>
> I just read the update of the dictionary.lst file
> Thansk for that
>
> I've a question though
> As en_GB thesaurus uses the same file as en_US, why not filling the .lst
> file with the two lines idependantaly of the language ?

I have made only a little 3-line patch:

--- dictionaries/en_GB/dictionary.lst   2005-02-21 13:07:04.000000000 +0100
+++ dictionaries.britishthesau/en_GB/dictionary.lst     2005-12-03
21:58:27.000000000 +0100
@@ -1,2 +1,3 @@
 DICT en GB en_GB
 HYPH en GB hyph_en_GB
+THES en GB th_en_US_v2
--- dictionaries/en_US/makefile.mk      2005-09-08 19:57:34.000000000 +0200
+++ dictionaries.britishthesau/en_US/makefile.mk        2005-12-04
03:26:45.000000000 +0100
-.IF "$(DIC_ALL)$(DIC_ENUS)"!=""
+.IF "$(DIC_ALL)$(DIC_ENUS)"!="" || "$(DIC_ALL)$(DIC_ENGB)"!=""

 ALLTAR : $(MISC)$/th_en_US_v2.don
--- dictionaries/prj/build.lst  2005-11-11 12:12:19.000000000 +0100
+++ dictionaries.britishthesau/prj/build.lst    2005-12-07 21:33:40.000000000 
+0100
@@ -4,7 +4,7 @@
 di     dictionaries\cs_CZ      nmake   -       all     di_cs_CZ di_diclst NULL
 di     dictionaries\da_DK      nmake   -       all     di_da_DK di_diclst NULL
 di     dictionaries\de_DE      nmake   -       all     di_de_DE di_diclst NULL
-di     dictionaries\en_GB      nmake   -       all     di_en_GB di_diclst NULL
+di     dictionaries\en_GB      nmake   -       all     di_en_GB di_en_US
di_diclst NULL
 di     dictionaries\en_US      nmake   -       all     di_en_US di_diclst NULL
 di     dictionaries\it_IT      nmake   -       all     di_it_IT di_diclst NULL
 di     dictionaries\ru_RU      nmake   -       all     di_ru_RU di_diclst NULL

Separating WordNet thesaurus is a good idea, but I didn't want to do
big changes in the source.

>
> Do I miss something ?
> What if --with-dic is not set ? all is written ?

Yes, it is, with the right en_GB and en_US thesaurus declaration:

HYPH da DK hyph_da_DK
HYPH de DE hyph_de_DE
DICT en GB en_GB
HYPH en GB hyph_en_GB
THES en GB th_en_US_v2
DICT en US en_US
HYPH en US hyph_en_US
THES en US th_en_US_v2
DICT it IT it_IT
HYPH it IT hyph_it_IT
HYPH ru RU hyph_ru_RU

Best regards,

Laci

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