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http://www.openoffice.org/issues/show_bug.cgi?id=53688





------- Additional comments from [EMAIL PROTECTED] Sat Sep  3 05:42:53 -0700 
2005 -------
Matthias,

Many thanks for your point by point response.

> (1) the horizontal bars of [ and ] are too thick.
Cannot confirm this. But note that sometimes one and the same formula is
rendered slightly different. Maybe this explains things.

I've posted Issue 54184 with more detail.
                      -------------------------------

> (2) the two bars of = are not of equal thickness.
Yes, this is true. However there was already an issue dealing with the worse
rendering quality compared with OOo1.1.x: issue 44668.
It's closed in the meantime but the equation sign problem you describe is not
fixed. We should open a new issue spoecific to this?

Your issue 54182 addresses this
                     -------------------------------
> The bar over the A is not bold.
It is, at least for me with Zoom=100%
       
I find, with 1.9.125 that the cut-off point is 191.  i.e. >= a zoom of 191 the
horizontal over bar is bold, not < 191.
I've posted this as Issue 54185
                     ------------------------------
> The bar over the first a does not cover the complete bracketed expression.
"Bar" is not the correct thing here. "bar{}" is supposed to work for one
character only. What you are probably looking for is "overline{}", to be found
in the lower left corner of the same symbol dialog. I admit this is a bit 
confusing.

Overline is exactly what I need - thanks.
                        ----------------------------
> The bar over the first a does not cover the complete bracketed expression.
"Bar" is not the correct thing here. "bar{}" is supposed to work for one
character only. What you are probably looking for is "overline{}", to be found
in the lower left corner of the same symbol dialog. I admit this is a bit 
confusing.

> The bar over the second a seems more ober the i subscript than the a
Maybe "left [ {bar a} rsub {i j} right ]" is what you are looking for in the
second case. Here the bar is over the a only, due to the brackets.

Again, that's what I should have done.  I has thought of the {} pair a being
rather like a function parenthesis i.e. collecting all the things the function
operates on.
                         ------------------------
Thanks for your help.  This has improved things and left some unresolved issues.

Colin W.










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