On Sun, 30 May 2004, Giuliano Pochini wrote: > On Wed, 26 May 2004 09:52:06 +0200 (CEST) > Jaroslav Kysela <[EMAIL PROTECTED]> wrote: > > > > > ALSA does not know about this. All period sizes must be equal. > > > > > > I thought about this again. Are you sure all periods must be aqual ? > > > When I record or play something using unequal periods, sound is perfect. > > > It means ALSA reads and writes the last (sometimes a lot) smaller period > > > as well. > > > > The driver must not acknowledge the settled period with the midlevel and > > application before the specified time. Of course, if you're running into > > a rounding problem, you can acknowledge more periods at one time. > > In other cases, it's not very practical to program hardware to use > > different period sizes, because you need more interrupts for processing. > > My question was about your sentence: "All period sizes must be equal". Is it > true ? It seems quite strange to me because ALSA passes a buffer size that
Yes, the time distance between period boundaries must be equal in longer term. Of course, interrupt/hardware latencies might shift the interrupt processing a few samples after. > is not multiple than the period size almost always. This is not a problem in I don't say that periods * period_size == buffer_size. It's another special case. > my case because the s-g list is generic enough to handle it. Yes, that's right. Jaroslav ----- Jaroslav Kysela <[EMAIL PROTECTED]> Linux Kernel Sound Maintainer ALSA Project, SuSE Labs ------------------------------------------------------- This SF.Net email is sponsored by: Oracle 10g Get certified on the hottest thing ever to hit the market... Oracle 10g. Take an Oracle 10g class now, and we'll give you the exam FREE. http://ads.osdn.com/?ad_id=3149&alloc_id=8166&op=click _______________________________________________ Alsa-devel mailing list [EMAIL PROTECTED] https://lists.sourceforge.net/lists/listinfo/alsa-devel