Sounds like what you want is:
if(your_condition)
{
cond1;
cond2;
cond3;
}
else
{
cond1;
cond2;
}
Bill
----- Original Message ----- From: Ton Sieverding
To: [email protected]
Sent: Thursday, February 15, 2007 1:53 PM
Subject: Re: [amibroker] AFL syntax for nested IIF ?
Yes you're right, it's impossible to have more actions in one single IIF
statement. And therefore the following statement is like you already told me
not correct :
IIF(Barnum > 5, This = 10 AND That = 20 AND Something = 30, Null );
I did a simple DebugView as Graham suggested. First the condition High>4 and
Low>4 are always true and therefore I got HighestHigh = 20 and LowestLow = -
10. Second the condition High>40 and Low>40 are always false and I got
HighestHigh = {Empty} and LowestLow = {Empty}. See pictures DI1 and DI2.
Then I tried the combination of the two actions in one single IIF and got
wrong answers. Although I did not get syntax errors. See DI3 and DB4.
Thanks again for the support ...
Ton.
----- Original Message -----
From: Graham
To: [email protected]
Sent: Thursday, February 15, 2007 10:27 AM
Subject: Re: [amibroker] AFL syntax for nested IIF ?
This statement is NOT correct ===>>> IIF(Barnum > 5, This = 10 AND That =
20 AND Something = 30, Null );
The email I sent with each variable independantly assigned is the only way
to do this
Here it is again
Here is correct and only method using IIF to create the arrays of values
for each variable
highbar = iif(barnum < 21, C , null );
lowbar = iif(barnum < 21, C , null );
range = iif(barnum < 21, C, null);
--
Cheers
Graham
AB-Write >< Professional AFL Writing Service
Yes, I write AFL code to your requirements
http://www.aflwriting.com
On 15/02/07, Ton Sieverding <[EMAIL PROTECTED]> wrote:
Thanks. No my problem is not how to use nested conditions in the double
IIF. That's fully explained in the manual. My problem is how to include several
actions in the IIF. Since the IIF is an array supporting IF this could create a
problem. Of course there are many solutions and Herman as well as Graham showed
some of them but that's not what I was looking for. Please read my answers to
Herman and Graham. It seems that Bill gave me the correct answer ...
Ton.
----- Original Message -----
From: mrdavis9
To: [email protected]
Sent: Thursday, February 15, 2007 3:48 AM
Subject: Re: [amibroker] AFL syntax for nested IIF ?
Amisiev, I just created this nested iff for checking the last three
days of
the close. Is this the kind of thing that you had in mind? You can keep
adding as many more iff statements as you like. Ron D
/*This nested IIf will return a 1 if todays Close, is greater than
(yesterdays Close, OR the two days ago Close, OR the three days ago
Close).
If todays close is NOT greater than any of the last three closes, then
this nested iff will return a 0.*/
NestedIIf=IIf(C>Ref(C,-1),1,IIf(C>Ref(C,-2),1,IIf(C>Ref(C,-2),1,0)));
Plot(NestedIIf,"rd",colorRed,styleLine);
----- Original Message -----
From: "amsiev" <[EMAIL PROTECTED]>
To: <[email protected]>
Sent: Wednesday, February 14, 2007 11:39 AM
Subject: [amibroker] AFL syntax for nested IIF ?
> What's the syntax in AFL for a double IF with following structure ?
>
> IF True
> Do This ;
> Do That ;
> Do anything;
> Endif
>
> I'm working with arrays so I must use the double IF but my problem is
> that I just cannot get the correct syntax. There are in fact two
> problemens. First I only want the IIF to do something when the
> condition is true. Therefore I don't want the third part in case the
> IIF is false or the 'Do if false'. Second I want the IIF to do
> several things. Not just one. Following syntax is wrong. So what's
> the correct one ?
>
> IIf(BarNumAct<=21,
> {
> Highs[BarNumAct] = Close;
> Lows[BarNumAct] = Close;
> Range[BarNumAct] = (High - Low)/2;
> }
> ,"");
>
>
>
> Please note that this group is for discussion between users only.
>
> To get support from AmiBroker please send an e-mail directly to
> SUPPORT {at} amibroker.com
>
> For NEW RELEASE ANNOUNCEMENTS and other news always check DEVLOG:
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>
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>
>
>
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