Hi - Close, it is Exrem that removes all signals until opposite signal is 
generated. Flip, after a True, will continue to return True until it comes 
to a True in the 2nd array. I think it is convenient to look at it as Signal 
( buy, sell, use Exrem ) vs. State ( in long, in short, use Flip ) In your 
case, if you have 2 arrays...

1101101111000000111 // in buy zone, occasionally drops into neutral 
territory
0000000000111111000 // in sell zone

then after doing
InLong = Flip( InBuyZone, InSellZone );
you will have

1101101111000000111 // in buy zone
0000000000111111000 // in sell zone
1111111111000000111 // in long, here is the filter you wanted I think?


----- Original Message ----- 
From: "levibreidenbach" <lev...@comcast.net>
To: <amibroker@yahoogroups.com>
Sent: Monday, October 19, 2009 11:15 AM
Subject: [amibroker] Re: MA cross with %filter


> Hello:
>
> I'm still having difficulty understanding both the flip() and exrem() 
> function.  Can somebody help to explain them.  I've read documentation, 
> but it is fairly brief.
>
> Does flip remove all signals until a opposite signal is generated?  Not 
> sure if I'm understanding it.
>
> Thanks
>
> Levi
>
> --- In amibroker@yahoogroups.com, "levibreidenbach" <lev...@...> wrote:
>>
>> Hello:
>>
>> Fairly new to Amibroker with a question regarding MA crossover.  This is 
>> probably very simple to code, but I can't seem to wrap my head around it. 
>> I would like to have a filter that I include with buy logic as follows: 
>> Using S&P500 data, whenever price moves above 65 week moving average by 
>> 1%, filter = 1.  Whenever price moves below MA by 1% filter = 0.
>>
>> The part I'm getting hung up on is what happens in between filter.  Say 
>> price trends down from buy zone (1.01*65 week MA), but doesn't close 
>> below sell zone (.99*65 week MA).  Then price comes back up above 1% buy 
>> filter.  During this period, the filter should always = 1.  But if it 
>> crosses 1% sell filter, it should become 0 until it crosses above 1% buy 
>> filter.
>>
>> I think I'm making this much more confusing than it needs to be.  I'm 
>> sure there is a very simple way to program this - that's what I'm looking 
>> for.
>>
>> Thanks ahead of time,
>>
>> Levi
>>
>
>
>
>
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