Looking for a AM transmitter homebrew ok. around 500 to kw output. have
lots of ba's to trade or will consider a boxed ts 850sat with all filters
for the right transmitter if anyone is interested..
73 Tony wa4jqs
QBE ZUT DE WA4JQS SK
A1-OP FISTS # 10573
EXTRA - HEAVY
From [EMAIL PROTECTED] Sat Aug 20 10:53:33 2005
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From: "Bob Bruhns" <[EMAIL PROTECTED]>
To: "Discussion of AM Radio" <amradio@mailman.qth.net>
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Subject: Re: [AMRadio] AM Audio
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Yes, that will work. But remember, you want equal
voltages across the resistor and the inductor.
Surprisingly, this will not be 50% of the applied
voltage, but it will be about 71% of the applied
voltage. This adds up to about 1.414 times the applied
voltage! You should confirm this by measuring both
voltages directly.
This happens because the impedance of the inductor is
reactive, and the current is equal, so the phases of
the voltages differ by 90 degrees. This phase shift
causes a partial cancellation when the voltages are
added, so 71 + 71 = 100 instead of 142. It's
interesting to observe.
Bacon, WA3WDR
----- Original Message -----
From: "Geoff" <[EMAIL PROTECTED]>
To: "Discussion of AM Radio" <amradio@mailman.qth.net>
Sent: Saturday, August 20, 2005 10:30 AM
Subject: [AMRadio] AM Audio
Well, I completed the task yesterday of installing a
Reactor for the
250TH rig.
(Push-pull Class C 250TH link-coupled final,
modulated by push-pull
Class B 250TH modulator)
http://w5omr.shacknet.nu:81/~w5omr/hamstuff/AM-Stuff/Titanic/modulator/new_titanic.jpg
Six inductors in series, 5 of which are known values
10Hy @ 500mA
10Hy @ 500mA
9.9Hy @ 500mA
12Hy @ 400mA
16Hy @ 450mA
(unknown)
The unknown choke is 1/3 larger than the 16Hy @ 450mA
choke and the
unknown choke is the largest in the chain,
physically. I'm going to
'assume' it's a minimum of 10Hy. Eventually, I will
take it out of the
lineup, feed about 10vAC through it, and a 1k
potentiometer, and adjust
the pot until the voltage across it, matches the
voltage dropped across
the choke. Thanks to John/WA5BXO for help in that
area:
__________________
by equalizing the voltage across the resistor and
choke results in the creation of a resistance that is
equal to XL of the choke at 60 CPS.
Measure the resistance of the variable resistor after
equalizing the voltage drops and you have the XL of the
choke at 60 cps.
L = XL / 2 * pi * F
L = XL / 6.28 * 60
L = XL / 376.8
Divide the resistance by 376.8 and you have the
inductance.
___________________
I will do that, soon.
Still using 9uF of coupling capacitance @ 4kVDC
(because those two caps
were still paralelled together and it was easier) and
this morning, was
able to work (among several other stations)
John/W5GI, on Lake Travis
near Austin, TX.
John is working with the guys who are continuing
development on the
'Flex Radio' software-based, computer-controlled
radio transciever system.
(http://www.flex-radio.com/)
He sent me a screen-shot of how my audio currently
appears on the air.
A Lot of information is on this screen.
http://w5omr.shacknet.nu:81/~w5omr/pictures/w5omr_frm_w5gi.jpg
Would appreciate your comments.
---
73 = Best Regards,
-Geoff/W5OMR
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