Hi Jim, What I said was, or tried to say, when a Class C rig is unloaded so as to draw less current, that is, to tune the loading and plate circuit so that the plate dip is lower current than it was when it is tune up for max. The plate voltage will stay about the same but the plate current is less and you have less RF output as well of course. In this scenario the ratio of Ep / Ip is greater. The Z that the modulator sees is greater.
Now if the plate voltage is lowered with out retuning anything, the plate current will fall as the plate voltage falls and the ratio of the two remains the same. Basically when a class C rig is set and not retuned, the Ep:Ip ratio is set and the plate current should follow the plate voltage up and down linearly. The RF should follow the plate voltage up and down as well. Some tubes and circuits need a little help with this. Such as using grid leak resistance instead of a fixed supply if the stage is to be modulated. The grid leak resistance will allow the grid voltage to fluctuate a little with the audio as the plate current goes up and down. This actually helps to keep the ration of IP to EP constant. The grid leak resistor is something of a self regulator for the ratio. The screen grid tubes have a whole other set of things that can be done to help the plate current to plate voltage ratio remain constant. There was a discussion awhile back about the plate voltage to plate current ratios. Some one was saying that a circuit will lose efficiency if the plate voltage is reduced. This is only true if the person changes the loading or tuning. What they probably meant was that if you reduce the voltage and try to retune to get the same power out that you would have less efficiency. The only thing that should happen when plate voltage is reduced is that the power input goes down and the RF power also goes down. If a rig with a plate supply of 600V is putting out 100 watts into 50 ohms the RF voltage would be 70.7 volts RMA. When the plate voltage is reduced to 300V the rig should put out 25 watts with RF voltage of 35.35 RMS on the load. Here is a chart. 600V EP 200ma IP DC input power = 120 watts RF output 100 watts Plate dissipation = 20 watts EFF = 83 percent EP/IP = 3000 ohms modulator load Z Now let's go down to 300 volts on the plate 300V EP 100ma IP DC input power = 30 watts RF output 25 watts Plate dissipation = 5 watts EFF = 83 percent EP/IP = 3000 ohms modulator load Z -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Jim Wilhite Sent: Tuesday, February 12, 2008 11:36 AM To: amradio@mailman.qth.net Subject: [AMRadio] RE: Using a Ranger as a driver I forgot to mention John, you might explain how a Class C final sees higher impedance when the plate voltage is lowered. As I recall Zp is = Ep/(2X) Ip. So a Ranger with 600 V. on the plate with 120 ma. is seeing ~ 2500 ohms. With 300 volts at the same current, it should be seeing ~1250. Zp. Maybe this will help some of these people and you are much more eloquent than I. Jim/W5JO ______________________________________________________________ Our Main Website: http://www.amfone.net AMRadio mailing list Searchable Archives: http://www.mail-archive.com/amradio@mailman.qth.net/ List Rules (must read!): http://w5ami.net/amradiofaq.html List Home: http://mailman.qth.net/mailman/listinfo/amradio Help: http://mailman.qth.net/mmfaq.html Post: mailto:AMRadio@mailman.qth.net To unsubscribe, send an email to [EMAIL PROTECTED] with the word unsubscribe in the message body. ______________________________________________________________ Our Main Website: http://www.amfone.net AMRadio mailing list Searchable Archives: http://www.mail-archive.com/amradio@mailman.qth.net/ List Rules (must read!): http://w5ami.net/amradiofaq.html List Home: http://mailman.qth.net/mailman/listinfo/amradio Help: http://mailman.qth.net/mmfaq.html Post: mailto:AMRadio@mailman.qth.net To unsubscribe, send an email to [EMAIL PROTECTED] with the word unsubscribe in the message body.