Exactly... return the exit value and check for it in the main activity to
exit or continue on.
On Thu, Jan 14, 2010 at 4:51 AM, Sean Hodges <seanhodge...@googlemail.com>wrote:
> Ah, that makes things clearer. So you simply want to pass a signal
> back to the caller Activity, rather than pass it by reference to the
> callee?
>
> Well, seeing that you are already calling startActivityForResult() to
> launch NewActivity, you could just return an "exit" value back to the
> parent...
>
> public static final int EXIT_APP = 1;
>
> class NewActivity extents Activity {
> private void doExitMethod() {
> setResult(EXIT_APP);
> finish();
> }
> }
>
> class MyParentActivity extents Activity {
> protected void onActivityResult(int requestCode, int resultCode,
> Intent data) {
> if (resultCode == EXIT_APP) {
> finish();
> }
> }
> }
>
>
>
> On Thu, Jan 14, 2010 at 12:16 PM, Hannes H. <dub...@gmail.com> wrote:
> > Its more like that: if you are starting the application the first time,
> you
> > have to enter some initial settings. If you don't want to do that there
> > should be a button for exiting the app.
> >
> > Il giorno 14/gen/2010 05:08, "Kevin Duffey" <andjar...@gmail.com> ha
> > scritto:
> >
> > So it sounds like you are putting up a dialog that offers the user to
> exit
> > the application.. and from that you want to return the yes/no response
> back
> > to the main activity.. if yes, quit, if no, continue?
> >
> > On Wed, Jan 13, 2010 at 12:06 PM, Sean Hodges <
> seanhodge...@googlemail.com>
> > wrote: > > The parent ...
> >
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