A single LF is the expected output for CR LF sequences. Normalization is part of the deal with XML.
http://www.w3.org/TR/REC-xml/#sec-line-ends In short: Find a non-conformant XML parser or encode your content. On 23 Nov, 06:04, Android Humanoid <droid.hu...@gmail.com> wrote: > SAXParserFactory spf = SAXParserFactory.newInstance(); > SAXParser sp = spf.newSAXParser(); > > XMLReader xr = sp.getXMLReader(); > SearchHandler sh=new SearchHandler(); > xr.setContentHandler(sh); > String query="xml query"; > > Log.e("Query:Disaplay mail", query); > URL url=new URL(query); > InputSource is=new InputSource(); > is.setEncoding("UTF-8"); > is.setByteStream(url.openStream()); > xr.parse(is); > > This is the parser am using... SearchHandler extends DefaultHandler. > My problem is in XML file.. i have a node called "emial" under that > "content" is the attribute, in that content I'll get some text that > text is have \n and \r. > > Does my SearchHandler recognize the \n or \r symbol or should I use > any different parser. > On Nov 23, 9:31 am, Frank Weiss <fewe...@gmail.com> wrote: > > > Please provide more details. > > > 1. Since you mention "symbols", are you using a push or pull SAX parser? > > 2. Newlines between *opening* XML elements are typically ignored, not by the > > parser itself, but by the handler. > > 3. Newlines in a text node ("characters") are significant. Is this the case > > you are talking about? > > 4. Newlines in CDATA nodes should also be signifacnt. Is this the case you > > are talking about? > > 5. Newlines and carriage returns, 0x0A, 0x0D, are identical whether encode > > in Latin-1 or UTF-8. I doubt this is the issue. > > > Can you give a concrete example, please. -- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en