ImageButton constructor takes the context as input parameter
http://developer.android.com/reference/android/widget/ImageButton.html

b = new ImageButton(this);

Regards
Sarwar Erfan


On Nov 30, 3:27 pm, Sarwar Erfan <erfanonl...@gmail.com> wrote:
> Hi,
> You are adding the same ImageButton again and again.
> You are getting reference of some existing button:
>
> >   b = (ImageButton) findViewById(R.id.card_image);
>
> and adding that button to the view again and again! So, you are
> getting the runtime error.
>
> Hint: You need to create NEW ImageButtons if you want multiple image
> buttons.
> b = new ImageButton();
>
> Regards
> Sarwar Erfan
>
> On Nov 30, 3:18 pm, pedr0 <pulsarpie...@gmail.com> wrote:
>
> > Hi at all,
>
> > I have to put some ImageButton inside an LinearLayout, but I don't
> > know the number of this statically, so because I keep the data through
> > internet at run-time.
>
> > I solved this problem adding new child at the layout at run time after
> > the oncreate() functions is called in this way:
>
> > ImageButton b;
> > LinearLayout contanier = (LinearLayout)
> > findViewById(R.id.card_images_layout);
> > for (int i = 0; i < this.card.images.size(); i++) {
> >   b = (ImageButton) findViewById(R.id.card_image);
> >   b.setImageBitmap((this.card.images.get(i).getImage_data()));
> >  contanier.addView(b);
>
> > }
>
> > But I take this error
>
> > java.lang.IllegalStateException: The specified child already has a
> > parent. You must call removeView() on the child's parent first
>
> > Is my solution which is incorrect or I make wrong something?
>
> > Thanks a lot
>
> > pedr0

-- 
You received this message because you are subscribed to the Google
Groups "Android Developers" group.
To post to this group, send email to android-developers@googlegroups.com
To unsubscribe from this group, send email to
android-developers+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/android-developers?hl=en

Reply via email to