Hi,
I am launching a floating activity to be displayed on top of the
screen when a call is placed or received and I want this activity do
not interfere with the call, the user should be able to answer a call
and hang up.
With the following code I almost accomplish this, the only problem is
that after I slide the bar to answer a call the button to hang up is
not displayed. I am not sure if it is a limitation because the phone
dialer activity goes to onresume and it wont update the UI?? If this
is true, is there a way work around it??
protected void onCreate(Bundle savedInstanceState){
super.onCreate(savedInstanceState);
final Window window = this.getWindow();
window.setFlags(WindowManager.LayoutParams.FLAG_NOT_TOUCH_MODAL
|
WindowManager.LayoutParams.FLAG_WATCH_OUTSIDE_TOUCH,
WindowManager.LayoutParams.FLAG_NOT_TOUCH_MODAL |
WindowManager.LayoutParams.FLAG_WATCH_OUTSIDE_TOUCH);
WebView webView = new WebView(this);
loadContent(webView);
setContentView(webView);
window.setGravity(Gravity.TOP);
window.setLayout(480,100);
WindowManager.LayoutParams lp = window.getAttributes();
lp.dimAmount= 0.0f;
lp.alpha = 1.0f;
window.setAttributes(lp);
...
}
This activity is displayed for a few seconds and then is closed but I
want it to be as seamless as possible and if the users does not see
the hang up button it is going to be a bit awkward.
I do not want to display the information in this activity in a toast
or a notification. In case the user finds it intrusive I have an
option to disable it (for instance it is disabled by default).
Regards,
Juan
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