Don't do: msg.what=1
Do: msg.arg1=1 Then, on the receiving side, your value will be: msg.arg1 On Sat, Oct 1, 2011 at 3:29 PM, Kristoffer <kris.isak.v...@gmail.com> wrote: > Hello. > > Iam having some trouble sending message from a thread back to the > "main" thread. > > I just need to send a integer just so i know what just happend in the > thread. > > This is what i use right now, > > Message msg = Message.obtain(); > msg.what = 1; > progressHandler.sendMessage(msg); > > - - - - - > > private Handler progressHandler = new Handler() { > @Override > public void handleMessage(Message msg) { > > Toast.makeText(getApplicationContext(), msg.toString(), > Toast.LENGTH_LONG).show(); > > This will show me: > { what=1 when=somenumbers } > > Is there a way so i just could "grabb" the Int 1 in this case? > > Iam then going to build if statments depends on the integer > > > -- > You received this message because you are subscribed to the Google > Groups "Android Developers" group. > To post to this group, send email to android-developers@googlegroups.com > To unsubscribe from this group, send email to > android-developers+unsubscr...@googlegroups.com > For more options, visit this group at > http://groups.google.com/group/android-developers?hl=en > -- Mark Murphy (a Commons Guy) http://commonsware.com | http://github.com/commonsguy http://commonsware.com/blog | http://twitter.com/commonsguy _The Busy Coder's Guide to Android Development_ Version 3.6 Available! -- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en