That's not what you want. It sounds like you want a largest dimension? There is some hidden code for getting this, but it is not completely correct. We can make a public method for it, but it will need to be fixed to be more accurate.
On Fri, Dec 9, 2011 at 4:13 AM, guich <guiha...@gmail.com> wrote: > Hi Dianne, > > Lemme explain my problem. > > All my application is drawn in an offscreen bitmap. When the > application starts, i get the maximum width/height of the screen and > create a square bitmap. This way, when screen rotates, i don't have to > create another bitmap. This prevents some crashes in my application. > > I'm aware of the "bug fix", i saw your comments in another thread. > What i'm asking is if Google can create a way to retrieve the size > with something like this: > > public Size getSizeOfScreenIncludingTaskbarArea() > or > public Size getSizeOfScreenForOrientation(int orientation) // VERTICAL > or HORIZONTAL > > This would help a lot. > > thanks for your time. > > Guich > > -- > You received this message because you are subscribed to the Google > Groups "Android Developers" group. > To post to this group, send email to android-developers@googlegroups.com > To unsubscribe from this group, send email to > android-developers+unsubscr...@googlegroups.com > For more options, visit this group at > http://groups.google.com/group/android-developers?hl=en > -- Dianne Hackborn Android framework engineer hack...@android.com Note: please don't send private questions to me, as I don't have time to provide private support, and so won't reply to such e-mails. All such questions should be posted on public forums, where I and others can see and answer them. -- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
