Hi
You're complicating.
String stripped = "";
for (int i = 0; i < sss1.lenght(); i++)
if (sss1.charAt(i) >= '0' && sss1.charAt(i) <= '9')
stripped += sss1.charAt(i);
int start = sss1.indexOf(sss0);
int stop = start + sss0.lenght();
Hope it helps.
BTW, this group is for Android related questions, not Java questions.
On Thu, Dec 15, 2011 at 11:32, Abhishek Kumar Gupta <akgaec2...@gmail.com>wrote:
> I am having a string(number) with special characters. I want to search for
> a sub-string(comprising of digits only) & also I want to detect the
> starting index & ending index of matching sub-string in the string. For
> example: main string: *(+91)-1-231-212 12-31*
> Sub-string to search: *1212*
>
> Currently I am using the following code to do this but in place of *1212*,it
> searched for *12312*. For other cases, it works fine.
>
> String sss0 = "1212";
>
> String sss1 = "(+91)-1-231-212 12-31";
>
> sss0 = sss0.replaceAll("[^\\d]","");
>
> System.out.println("*************************"+sss0);
>
> String ptn = "" + sss0.charAt(0);
>
> for(int jj=0; jj<sss0.length()-1; jj++){
>
> ptn += "[^" + sss0.charAt(jj) + sss0.charAt(jj+1) + "]*?" +
> sss0.charAt(jj+1);
>
> }
>
> System.out.println("ptn: " + ptn);
>
> Pattern p300 = Pattern.compile(ptn);
>
> Matcher m300 = p300.matcher(sss1);
>
> if(m300.find()){
>
> System.out.println("start, stop: " + m300.start() + "," +
> (m300.end()-1 ));
>
> System.out.println("substring: " + sss1.substring(m300.start(),
> m300.end()));
>
> }
>
> *Actually I have to ignore special characters in the main string during
> searching for the sub-string*.Please help me. Thanks in advance.
>
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