Dear all,this is my first time posting on google in general and this
post may not be related to above topic but trust me, I am writing it
out of desperacy. I could NOT get anywhere suitable to post it and I
need your help. Forgive me for mixing butter and milk !
my Custom search url :
https://www.googleapis.com/customsearch/v1?key=MY-KEY-HERE&cx=LONG-NUM:CX-ID&q=Latest
from NASA&alt=json is working perfectly on the browser but invoking
custom search from java code(all of the below codes are throwing the
same exception: java.net.ConnectException: Connection refused:
connect).I know I have valide key and CX values and google API
explorer proved me right as well as any browser. here are a few snipet
that all throw the same execption:
(1)
public void method1(){
String search = "NASA latest research";
String charset = "UTF-8";
try{
//Reader reader = new InputStreamReader(new URL(the
url).openStream());
// Reader reader = new InputStreamReader(new
URL(google).openStream(), charset);
Reader reader = new InputStreamReader(new URL(google+
URLEncoder.encode(search, charset)).openStream(), charset);
GoogleResults results = new Gson().fromJson(reader,
GoogleResults.class);
//List<com.google.api.services.customsearch.model.Result>
result = new Gson().fromJson(reader, List.class);
System.out.println(results.getResponseData().getResults().get(0).getTitle());
System.out.println(results.getResponseData().getResults().get(0).getUrl());
}catch(MalformedURLException urle){
urle.printStackTrace();
}
catch(UnsupportedEncodingException ence){
ence.printStackTrace();
}
catch(IOException ioe){
ioe.printStackTrace();
}
}
(2) String google = "the url";
public void search0(){
try{
GoogleSearchQueryFactory factory =
GoogleSearchQueryFactory.newInstance("MY-KEY-HERE");
WebSearchQuery query = factory.newWebSearchQuery();
PagedList<WebResult> response =
query.withQuery("Latest from NASA").list();
System.out.println(response.getCurrentPageIndex());
System.out.println(response.getEstimatedResultCount());
System.out.println(response.getMoreResultsUrl());
System.out.println(response.getPages());
for (WebResult result : response) {
System.out.println(result.getTitle());
System.out.println(result.getContent());
System.out.println(result.getUrl());
System.out.println("=======================================");
}
}catch (Exception e) {
e.printStackTrace();
}
}and
(3)
public class GoogleQuery {
private final String HTTP_REFERER = "http://www.example.com/";;
public GoogleQuery() {
makeQuery("questio verum");
makeQuery("info:http://frankmccown.blogspot.com/";);
makeQuery("site:frankmccown.blogspot.com");
}
private void makeQuery(String query) {
System.out.println("\nQuerying for " + query);
try{
// Convert spaces to +, etc. to make a valid URL
query = URLEncoder.encode(query, "UTF-8");
String url_="the url";
URL url = new URL(url_);
URLConnection connection = url.openConnection();
connection.addRequestProperty("Referer", HTTP_REFERER);
// Get the JSON response
String line;
StringBuilder builder = new StringBuilder();
BufferedReader reader = new BufferedReader(
new InputStreamReader(connection.getInputStream()));
while((line = reader.readLine()) != null) {
builder.append(line);
}
String response = builder.toString();
JSONObject json = new JSONObject(response);
System.out.println("Total results = "
+json.getJSONObject("responseData").getJSONObject("cursor").getString("estimatedResultCount"));
JSONArray ja =
json.getJSONObject("responseData").getJSONArray("results");
System.out.println("\nResults:");
for (int i = 0; i < ja.length(); i++) {
System.out.print((i+1) + ". ");
JSONObject j = ja.getJSONObject(i);
System.out.println(j.getString("titleNoFormatting"));
System.out.println(j.getString("url"));
}
}
catch (Exception e) {
System.err.println("Something went wrong...");
e.printStackTrace();
}
}
public static void main(String args[]) {
new GoogleQuery();`
}
}
None of the above would work and all return the same e. does it mean
this can work only via
the :com.google.api.services.customsearch.Customsearch. well ,I have
tried that too but with compiler errors on these deprecated mthods:
I really need a urgent help.Thanks in Advance !! Really grateful 1
thanks
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