Thank you very much, you saved me a lot of time!!!

On May 8, 8:07 pm, jseghers <jsegh...@cequint.com> wrote:
> I'm posting this to share the lessons I learned while working with
> IntentService.
>
> IntentService has a single constructor that takes a string argument
> "name". The documentation has no description of what name is used for.
> In looking at the sources, I found that its only use is in naming the
> worker thread for the IntentService. This thread is named IntentService
> [name].
>
> I initially implemented the constructor of the derived class to also
> take a String argument and passed it along to the derived class. This
> is wrong. This will cause the startService() call to generated a
> java.lang.InstantiationException in the application containing the
> service i.e. you don't get the exception in the application calling
> startService(). A clue to the actual problem is a little further up in
> the logs:"newInstance failed: no <init>()"
>
> The derived class must have a Default constructor and that constructor
> must call super() passing a string for the name component of the
> worker thread name.
>
> public class MyIntentService extends IntentService
> {
>     public MyIntentService() {
>         super("MyIntentService");
>     }
>
>     @Override
>     protected void onHandleIntent(Intent intent)
>     {
>         // Handle events on worker thread here
>     }
>
> }
>
>

--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google
Groups "Android Developers" group.
To post to this group, send email to android-developers@googlegroups.com
To unsubscribe from this group, send email to
android-developers-unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/android-developers?hl=en
-~----------~----~----~----~------~----~------~--~---

Reply via email to