You will have to sort your data once you get it. You can't control the order
it's processed. If you know for a fact that it will only be 4 items, you
could create an array of size 4, then stick the data in the specific index
spot of the array. Or you can add it to a list then sort it. That is an odd
XML tho. I've not seen xml return something like that...are you responsible
for the XML being returned, or have no control over it?
On Mon, Feb 1, 2010 at 2:26 AM, Sasikumar.S <sasikumar.it1...@gmail.com>wrote:
> Thank U for responding previous Questions.
>
> One more thing Guys.
>
> Now i'm getting one more doubt in that.
>
> I need to parse the below XML file:
>
> <item>
> <2>2item</2>
> <3>3item</3>
> <1>1item</1>
> <4>4item</4>
> </item>
>
> In that i'm fetching data from <1>, <2>,<3> & <4>.
> But i'm getting value as <2>, <3>, <1> & <4> in order wise.
>
> How to get in my wish order?.
>
> Please give some idea guy?..
>
>
> On Mon, Feb 1, 2010 at 10:29 AM, Frank Weiss <fewe...@gmail.com> wrote:
>
>> SAXParser does NOT parse line by line. That's incorrect. What you need is
>> something like this:
>>
>> @Override
>> public void characters(char[] ch, int offset, int count) {
>> sb.append(ch, offset, count);
>> }
>> @Override
>> public void endElement(String namespaceUri, String localName, String
>> qName) {
>> if (localName.equals("title"))
>> title = sb.toString();
>>
>>
>>
>>
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>
>
>
> --
> Thanks & Regards
> Sasikumar.S
>
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