*notifyDataSetChanged

it seems like removeview is not supported operation

if you can change the underlying data then call **notifyDataSetChanged i
believe.

then gridview should redraw and if you have added or removed from ur
underlying data then it should reflect in gridview.

this is my theory. May or may not work
*
On Mon, Mar 22, 2010 at 10:59 AM, tilo1583 <tilo1...@gmail.com> wrote:

> I am using GridView using AdapterView. Therefore, I cannot remove
> Views from the grid view,http://developer.android.com/reference/
> android/widget/AdapterView.html<http://developer.android.com/reference/%0Aandroid/widget/AdapterView.html>So,
>  this technique is not going to
> work.
> Do you know any other technique/ work around to remove views from an
> adapter view?
>
> - Tilo
>
> On Mar 19, 2:59 pm, social hub <shubem...@gmail.com> wrote:
> > LinearLayout pa=(LinearLayout)la.getParent();
> >             if(pa!=null){
> >                 Log.i(TAG,"removed view la parent====>");
> >                 pa.removeView(la);
> >                 mNetworkLayout.removeView(la);
> >             }
> >
> > this one works for me.
> >
> > but u should know ur parent first
> >
> > lets say ur child parent is linearLayout then cast the parent to
> > linearlayout of your child
> >
> > LinearLayout ll=(LinearLayout)child.getParent();
> >
> > if (ll ! =null){
> > ll.remove(child)
> >
> > }
> >
> > I am not sure if it works for you let me know
> >
> >
> >
> > On Fri, Mar 19, 2010 at 9:12 AM, tilo1583 <tilo1...@gmail.com> wrote:
> > >  I tried your method, but it still does not work.
> >
> > > GridView g = (GridView)findViewById(R.id.gridview1);
> > > g.removeAllViews();
> >
> > > It still gives the same exception, as 'removeAllViews() is
> > > unsupported'
> >
> > > On Mar 18, 5:36 pm, social hub <shubem...@gmail.com> wrote:
> > > > what is the parent for the view u r fetching. if its the parent
> > > (gridview)
> > > > then I think will throw exception.
> >
> > > > I did removeviews before
> >
> > > > I had <linearlayout android:id="@+id/layout"> imgview1
> > > > imgview2</linearlayout>
> >
> > > > bascilly oncreate u get reference to lineralayout
> > > > using
> >
> > > > LinearLayout l=findviewbyid(r.id.layout)
> >
> > > > then lets say onclick event of button u call
> >
> > > > l.removeviews();
> >
> > > > this shud work. you can try working along these lines.
> >
> > > > in your case you have to check what is the parent before u try to
> remove.
> >
> > > > This is based on my understanding of your problem. I can be wrong .
> >
> > > > On Thu, Mar 18, 2010 at 2:59 PM, tilo1583 <tilo1...@gmail.com>
> wrote:
> > > > > Hi Everyone,
> >
> > > > > I am very new to Android development, but I am not new to
> develoment
> > > > > of UIs.
> > > > > I am trying to run this piece of code.
> > > > > Basically, there is a GridView which contains a bunch of
>  ImageViews.
> > > > > To each of these image views I have added this
> > > > > onTouchListener as given below. However, the removeView statement
> > > > > throws an exception - "Unsupported operation".
> > > > > It is important for me to remove this view, because I need to
> attach
> > > > > it to another layout.
> >
> > > > > Any help is really appreciated!
> >
> > > > > this._pieceTouchListener = new OnTouchListener(){
> > > > >                        public boolean onTouch(View v, MotionEvent
> > > event) {
> > > > >                                 if(view != null)
> > > > >                                {
> > > > >                                        switch(action)
> > > > >                                        {
> > > > >                                            case
> > > MotionEvent.ACTION_DOWN:
> > > > >                                                try {
> >
> > > > >                                                        ViewGroup vg
> =
> > > > > (ViewGroup)v.getParent();
> > > > >                                                        //this line
> > > throws
> > > > > an exception
> >
> > > > > vg.removeView(v);
> >
> > > > >                                                } catch (Exception
> exc)
> > > {
> >
> > > > >  exc.printStackTrace();
> > > > >                                                }
> > > > >                                            ......
> > > > >                                        }
> > > > >                              }
> > > > >                        }
> > > > >  }
> >
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