On Wed, Nov 19, 2014 at 12:05 PM, Rob <[email protected]> wrote:

> I have two queries on resources and try to process the data once both
> queries have been finished. I tried to do this with the following code:
>
> var groupRes = $resource(baseUrl + "group/" + ":Id", { Id: "@Id" }, {});
> var group = groupRes.query();
> var taskRes = $resource(baseUrl + "task/" + ":Id", { Id: "@Id" }, {});
> var task = taskRes.query();
>
> var r, e;
> $q.all([group.$promise, task.$promise]).then(function (results) { r =
> results;
> }, function (error) { e = error;
> });
>
> However, neither of my two functions for $q.all(..).then(...) are being
> called and both r and e stay undefined.
>
> When I do a 'then' on just one of the promises everything works as
> expected.
>
> task.$promise.then(function (result) { ....
>
> How can I get this to work with $q.all?
>
>

Your code looks correct-ish, but human eyes and brains are notoriously bad
at determining code correctness. I suspect there is some minor typo-bug -
if you put this demonstration of the problem in a plunkr, someone will
likely spot it.

-- 
Kyle Cordes
http://kylecordes.com

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