Hello Lukas,
you missed a link from Bart Kiers answer?
http://stackoverflow.com/questions/6847971/antlr-identifier-with-whitespace
> Did i do anything wrong when i asked my question or does really nobody
> know a solution?
>
> Am 27.07.2011 19:39, schrieb Lukas Glowania:
>> Hi,
>>
>> i want identifiers that can contain whitespace.
>>
>> |grammar WhitespaceInSymbols;
>>
>> premise : ( options {greedy=false;} : 'IF' ) id=ID{
>> System.out.println($id.text);
>> };
>>
>> ID : ('a'..'z'|'A'..'Z')+ (' '('a'..'z'|'A'..'Z')+)*
>> ;
>>
>> WS : ' '+ {skip();}
>> ;
>> |
>>
>> When i test this with "IF statement analyzed" i get a
>> MissingTokenException and the output "IF statement analyzed".
>> I thought, that by using greedy=false i could tell ANTLR to exit afer
>> 'IF' and take it as a token. But instead the IF is part of the ID. Is
>> there a way to achieve my goal? I already tried some variations of the
>> greed=false-option, but without success.
>> Thanks in advance!
>>
>>
>
>
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