'Department' LIKE ($1000000000$ + "%" ) or $1000000000$ = " "
 
don't forget the blank between the double quotes

HTH
 
Kind Regards Conny
________________________________

Von: Action Request System discussion list(ARSList)
[mailto:arsl...@arslist.org] Im Auftrag von marti...@ad.jmu.edu
Gesendet: Montag, 13. Juli 2009 17:35
An: arslist@ARSLIST.ORG
Betreff: Allowing users to enter leading characters in search menu field


** 

Dear List,

 

I have a "Department" field (field ID 1000000000), with choices listed
in a "Department Form."  I want users to be able to either click on the
Menu button and see all choices, or enter one or more leading characters
and see the choices that begin with those letters.  (Eg, type in "Eco"
and then see "Ecology" and "Economics" in the menu.)

 

If I have no qualifications in my menu it shows all choices.

 

If my qualification says:

'Department' LIKE ($1000000000$ + "%" ) 

It works if the user enters a leading letter or two, but if there are no
leading letters it says, "(No entries in menu)."

 

I tried:

            $1000000000$ = $NULL$ OR 'Department' LIKE ($1000000000$ +
"%" ) 

But still got "(No entries in menu)."

 

'Department' LIKE ( "%"  + $1000000000$ +  "%" )

works if there are no leading characters, but if there are leading
characters, it offers choices in which the leading characters appear
anywhere in the Department name.  (Workable, but not ideal.)

 

Any suggestions?

(ARS 7.1 p3, RH Linux server, Oracle 10.2)

 

Dwayne Martin

James Madison University

 

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