The second statement should be

select count(*) from t9 where c104 like '1; %' or c104 like '% 1; %';

However I would rather use the view name of the user form which is user_x
instead of t9 because if you are writing code that needs to be migrated
across servers, writing SQL statements on the T tables may not be the best
idea unless in your environment you are absolutely sure that you have the
whole table structures migrated across systems maintaining the identical T
numbers for those tables across environments..

So I would rather prefer the statement

select count(*) from user_x where group_list like '1; %' or group_list like
'% 1; %';

This statement will be good for all environments irrespective of how careful
you are to ensure ideal case database migrations between different
environments...

As far as parsing the group ID's to real group names, if you absolutely have
to do it using direct SQL queries why not try writing a stored procedure to
do it? It may be a lot easier..

Joe
  -----Original Message-----
  From: Action Request System discussion list(ARSList)
[mailto:arsl...@arslist.org]on Behalf Of remedy.help
  Sent: Tuesday, February 16, 2010 5:09 PM
  To: arslist@ARSLIST.ORG
  Subject: Re: SQL help needed


  **
  What i need -->

  I need to pull out the group names from group list field(c104). Since it
contains the group id and not the group names i need to convert it back to
group names;

  Also can we do a select statement for group list field where we say

  select count(*) from t9 where c104 like '1';

  I am on oracle DB and the list i have checked for every other string
habits;

  regards



  On Tue, Feb 16, 2010 at 4:00 PM, Joe D'Souza <jdso...@shyle.net> wrote:

    **
    Have you tried retrieving the same using a simple select statement using
a like clause? I do not see a distinct advantage of using a cursor to
retrieve what you are trying to.

    Joe
      -----Original Message-----
      From: Action Request System discussion list(ARSList)
[mailto:arsl...@arslist.org]on Behalf Of remedy.help
      Sent: Tuesday, February 16, 2010 4:42 PM
      To: arslist@ARSLIST.ORG

      Subject: Re: SQL help needed


      **
      the error points to the Fetch statement Fetch C1 into
froup_id,group_name
      It will be great if somebody has done sql manipulations on the C104
filed of the t9(User Form)


      On Tue, Feb 16, 2010 at 3:37 PM, Joe D'Souza <jdso...@shyle.net>
wrote:

        **
        What is the error that you are getting?

        Joe
          -----Original Message-----
          From: Action Request System discussion list(ARSList)
[mailto:arsl...@arslist.org]on Behalf Of amit dw
          Sent: Tuesday, February 16, 2010 4:20 PM
          To: arslist@ARSLIST.ORG
          Subject: SQL help needed


          **
          Hello All,

          Below is the problem and way I was trying to handle it



          C_list contains comma separated values of group Id’s. this list
contains all the group id’s associated to a particular login name.



          C_list= (1,15005,800005,800003,800004,805)



          This variable will be holding up dynamically value in numbers.



          For group id numbers in simple sql statement we can get the result
corresponding name using the below query,



          Select c105,c106 from t10 where c106 in (1, 101,102,104).



          Same query when I tried transforming in a cursor it throws up a
compilation error. The error points out to a fetch statement where we try
and fetch the data from the cursor for one particular group id.



          Declare cursor c1 as select c105,c106 from t10 where c106
in(c_list);

          Begin

          Open c1;

          Loop

          Fetch C1 into g_num,g_name;

          dbms_output.put_line(g_name);

          EXIT WHEN C1%NOTFOUND;

          END LOOP;

          Close c1;

          End;



          Hope it explains the problem I am facing.

          Any suggestions/Comments or previously implemented code will be
helpful for me.

_______________________________________________________________________________
UNSUBSCRIBE or access ARSlist Archives at www.arslist.org
Platinum Sponsor:rmisoluti...@verizon.net ARSlist: "Where the Answers Are"

Reply via email to