Hi Philipp,
The quick answer is: don't use the ARS OO interface. You'll have to use the
procedural interface and sort out the enum values yourself. Look at
ARSOOform.pm. The code that produces your error-message is:
if ($fv->{'dataType'} eq "enum") {
if (ref($fv->{'limit'}->{'enumLimits'}) eq "ARRAY") {
$enums{$_} =
[...@{$fv->{'limit'}->{'enumLimits'}}];
}
elsif (exists $fv->{'limit'}->{'enumLimits'}->{'regularList'}) {
$enums{$_} = [...@{$fv->{'limit'}->{'enumLimits'}->{'regularList'}}];
} else {
print "Sorry. I'm not sure what to do with non-regularLists of
enums.\n";
print "(this enum is type \"", keys %{$fv->{'limit'}->{'enumLimits'}},
"\")\n";
print "listStyle = ", $fv->{'limit'}->{'enumLimits'}->{'listStyle'},
"\n";
die;
}
}
}
I find Data::Dumper very helpful for quickly getting to know the
data-structures returned by various API calls.
Cheers,
Rob Urban
-----Urspr?ngliche Nachricht-----
Von: Wollschlegel Philipp [mailto:philipp.wollschle...@alpiq.com]
Gesendet: Mittwoch, 25. M?rz 2009 13:09
An: arsperl-users@arsperl.org
Betreff: [Arsperl-users] Non-regularLists of enums
Greetings List,
I am trying to open a form with arsperl 1.91 like so:
$form = $connection->openForm(-form=> "CHG:Template");
While some forms work ok with the above method, I get the following error when
I try to open the above mentioned form:
Died at /usr/local/lib/perl/5.10.0/ARSOOform.pm line 74.
new connection object: (servername, username, )
caching field: Authoring Organization
datatype: char
caching field: z1D Char11
datatype: char
caching field: z1D_AssociationType02
datatype: enum
Sorry. I'm not sure what to do with non-regularLists of enums.
(this enum is type "customList")
listStyle =
destroying connection object: ars_Logoff called.
Am I using the wrong method to open the form?
Sincerely,
- Philipp Wollschlegel
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easily build your RIAs with Flex Builder, the Eclipse(TM)based development
software that enables intelligent coding and step-through debugging.
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