Emacs by default allocates a pty for subprocesses. There’s no way to do this 
portably, as many Lisps don’t support it, so UIOP won’t help you here. If 
you’re on SBCL and portability is not a concern, you can use sb-ext:run-program 
with a :pty keyword argument, as described in section 7.7.3 of the SBCL manual. 
Failing that, it’s probably best to use sudo -S.

phoebe

> On Jan 12, 2021, at 10:01 AM, Pierre Neidhardt <m...@ambrevar.xyz> wrote:
> 
> Hi!
> 
> I'd like to run a "sudo" command from Common Lisp.  The following works:
> 
> --8<---------------cut here---------------start------------->8---
> (uiop:launch-program '("sudo" "-S" "ls" "/root") :input :stream :output 
> *standard-output*)
> (format (uiop:process-info-input #v1) "MY-PASSWORD~%")
> (finish-output (uiop:process-info-input #v1))
> --8<---------------cut here---------------end--------------->8---
> 
> Note that I'm using the "-S" parameter of sudo.  From the man page:
> 
>> Write the prompt to the standard error and read the password
>> from the standard input instead of using the terminal device.
> 
> Without it, "sudo" terminate immediately.
> 
> Somehow, Emacs _does_ support calling the sudo process without the "-S"
> flag.  Try this:
> 
> --8<---------------cut here---------------start------------->8---
> (make-process :name "dummy" :command '("sudo" "ls" "/root"))
> --8<---------------cut here---------------end--------------->8---
> 
> and the "sudo" process is kindly waiting for input in the background.
> 
> Any idea why that is?
> Is it be possible to do the same in Common Lisp?
> 
> Cheers!
> 
> --
> Pierre Neidhardt
> https://ambrevar.xyz/

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