Dean,
Ok, I tested an alternative method without using importNode.
It's crude and probably the least efficient way to go but it
demostrates how to get around an unwanted parent node.
Given the xmlSubMenuNode points to the node: <subMenu>
Dim strChildNodesXml As String = xmlSubMenuNode.InnerXml()
'get all the <menuItem> s without the parent
Dim strRootNodeXml As String = "<menu>" & strChildNodesXml &
"</menu>" '-- add the root node
xmlSubMenu.LoadXml(strRootNodeXml) '-- load the string into the SubMenu
Menu2.DataSource = xmlSubMenu
Menu2.DataBind()
That said, I think the For Each .... childnode loop with importNode
is more efficient than having to parse and load the entire XML string
?
Regards, Paul
On 7/20/05, Paul N. Chu <[EMAIL PROTECTED]> wrote:
> Dean,
>
> Because the first xml doc has a <subMenu> parent node for
> <menuItems> underneath
> The Xpath pointed to the parent node and thus your code works fine.
>
> For Each nChild In xmlSubMenuNode.ChildNodes
> nChildForNew = xmlSubMenu.ImportNode(nChild, True)
> rootNode.AppendChild(nChildForNew)
> Next
>
> vs
>
> 'nChildForNew = xmlSubMenu.ImportNode(xmlSubMenuNode.FirstChild., True)
> 'rootNode.AppendChild(nChildForNew)
>
> But, for learning's sake, I would like to see an alternative method
> which would allow me to use ImportNode instead of doing the For each
> .... if possible.
>
> The importNode method only takes a xmlnode as a parameter and not a
> xmlnodelist. This prevents me from passing a nodelist of <menuItems>
> which could be changed in the code above by using SelectNodes instead
> of SelectSingleNode.
>
> ----
>
> Glad to see you're expanding the Fiala clan and that the son will have
> a younger sister to "fight" with. I wonder if "he/she" will have "hoop
> dreams" like dear ole Dad ?
> Not planning any visit but you never know...
>
> Dean, keep up the good work and thanks, Paul
>
>
>
>
> On 7/20/05, Dean Fiala <[EMAIL PROTECTED]> wrote:
> > Import node pulls in whatever node you tell it to. We were grabbing
> > too high up. Just do this instead and grab the first child of the sub
> > menu nodes which what you want....
> >
> > nChildForNew = xmlSubMenu.ImportNode(nChild.FirstChild, true)
> >
> > and you should be all set.
> >
> > The little boy is doing very well and is getting taller by the day and
> > talking up a storm. Also has a little sister now, 8 months old, who is
> > just starting to bug him because she can crawl and grab his toys.
> > When you coming out to lose in basketball again?
> >
> > On 7/19/05, Paul N. Chu <[EMAIL PROTECTED]> wrote:
> > > Hi Dean,
> > >
> > > How's your son doing ? He was just a wee wee guy "walking" around the
> > > neighborhood last time I was in town.
> > >
> > > Thanks for the code to do the looping.
> > > It works fine !!!
> > >
> > > I was curious how use the importNode method which seems to be designed
> > > for this.
> > > When I used the importNode the resulting submenu xml had the
> > > unwanted element: <subMenu> as the top element but I only wanted
> > > <menuitem> nodes which I could easily append to the root node <menu>.
> > >
> > > I changed the original code so I don't have the importNode version handy.
> > >
> > > I will try and followup on the other groups later.
> > >
> > > Thanks, Paul
> > >
> > >
> > > On 7/19/05, Charles Carroll <[EMAIL PROTECTED]> wrote:
> > > > CrossPost this to:
> > > > http://groups.yahoo.com/group/XmlToughQuestionsAspClassicAspNet/
> > > > and
> > > > http://groups.yahoo.com/group/DotNetXML/
> > > > tons of XML experts there may have suggestions to improve that code.
> > > >
> > > > On 7/18/05, Paul N. Chu <[EMAIL PROTECTED]> wrote:
> > > > > Here's is the basic code I have so far:
> > > > >
> > > > > '-- Build Top Full Horizontal Menu at Menu1 server control
> > > > > Dim menuXML As New System.Xml.XmlDocument
> > > > > Dim xmlNode As System.Xml.XmlNode
> > > > > menuXML.Load(Server.MapPath("CoStar.xml")) ' the Menu file
> > > > > Menu1.DataSource = menuXML
> > > > > Menu1.DataBind() ' Top Horiz Menu built
> > > > >
> > > > > '-- Build SubMenu Menu at Menu2 server control
> > > > > Dim xmlSubMenu As XmlDocument = New XmlDocument
> > > > > Dim xmlDeclaration As XmlDeclaration =
> > > > > xmlDoc.CreateXmlDeclaration("1.0", "utf-8", Nothing)
> > > > > Dim rootNode As XmlElement = xmlDoc.CreateElement("Menu")
> > > > > xmlDoc.InsertBefore(xmlDeclaration, xmlDoc.DocumentElement)
> > > > > xmlDoc.AppendChild(rootNode)
> > > > >
> > > > > Dim strMenuItemText As String = "Settlement" '-- Hardcoded here
> > > > > Dim myXPath As String =
> > > > > String.Format("/menu/menuItem[text='{0}']/subMenu",
> > > > > strMenuItemText)
> > > > >
> > > > > 'this should point to subMenu node for Settlement menuitem if the
> > > > > Xpath is right
> > > > > xmlNode = menuXML.SelectSingleNode(myXPath)
> > > > >
> > > > > ' ??? How to collect all the childNodes and copy to new document
> > > > > ' xmlNode.childNodes loop ? with appendChild etc ?
> > > > >
> > > > > Menu2.DataSource = xmlSubMenu
> > > > > Menu2.DataBind()
> > > > >
> > > > >
> > > > >
> > > > > On 7/18/05, Paul N. Chu <[EMAIL PROTECTED]> wrote:
> > > > > > Given the following xml , I would like to XPATH for the Placement
> > > > > or
> > > > > > Settlement menuitem and then construct another XML file shown
> > > > > below
> > > > > > from the childnodes of the subMenu node.
> > > > > >
> > > > > > <menu>
> > > > > > <menuItem>
> > > > > > <text>Placement</text>
> > > > > > <cssclass>highlighteditem</cssclass>
> > > > > > <subMenu>
> > > > > > <menuItem>
> > > > > > <text>Sub Item 3</text>
> > > > > > <url>page3.html</url>
> > > > > > </menuItem>
> > > > > > <menuItem>
> > > > > > <text>Sub Item 4</text>
> > > > > > <url>page4.html</url>
> > > > > > </menuItem>
> > > > > > </subMenu>
> > > > > > </menuItem>
> > > > > >
> > > > > > <menuItem>
> > > > > > <text>Settlement</text>
> > > > > > <cssclass>highlighteditem</cssclass>
> > > > > > <subMenu>
> > > > > > <menuItem>
> > > > > > <text>Sub Item 3</text>
> > > > > > <url>page3.html</url>
> > > > > > </menuItem>
> > > > > > <menuItem>
> > > > > > <text>Sub Item 4</text>
> > > > > > <url>page4.html</url>
> > > > > > </menuItem>
> > > > > > </subMenu>
> > > > > > </menuItem>
> > > > > > </menu>
> > > > > >
> > > > > >
> > > > > > This is the desired submenu xml that I would like to create:
> > > > > >
> > > > > > <menu>
> > > > > > <menuItem>
> > > > > > <text>Sub Item 3</text>
> > > > > > <url>page3.html</url>
> > > > > > </menuItem>
> > > > > > <menuItem>
> > > > > > <text>Sub Item 4</text>
> > > > > > <url>page4.html</url>
> > > > > > </menuItem>
> > > > > > </menu>
> > > > > >
> > > > > > Thanks, Paul
> > > > > >
> > > > > > On 7/18/05, getsmartpaul86 <[EMAIL PROTECTED]> wrote:
> > > > > > > Hi Xmlers,
> > > > > > >
> > > > > > > I'm looking for an example that would
> > > > > > > use xpath to search a document for a Node and then
> > > > > > > clone / copy that node and it's children to another xmldocument.
> > > > > > >
> > > > > > > I'm working with skmMenu by Scott Mitchell and have a Horizontal
> > > > > Top
> > > > > > > Menu and would like to search the menu xml nodes to find
> > > > > > > the current Top Level Menu and copy it's children
> > > > > > > and then show those nodes also in a left hand - navigation menu.
> > > > > > >
> > > > > > > Thus if the top menu has CatA , CatB, CatC
> > > > > > > then the xpath to CatB
> > > > > > > would find all the childnodes of CatB and then copy them
> > > > > > > to a new XML document.
> > > > > > >
> > > > > > > Thanks for your help, Paul
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > > Yahoo! Groups Links
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > >
> > > > >
> > > > >
> > > > >
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> >
> >
> > --
> > Dean Fiala
> > Very Practical Software, Inc
> > http://www.vpsw.com
> >
> >
> > --
> > Dean Fiala
> > Very Practical Software, Inc
> > http://www.vpsw.com
> >
> >
> >
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