How can I make ksh to pass exactly ONE back slash to _ast_regcomp()?
So far I tried it without success, either it passes 0 or 2 back
slashes to _ast_regex():
(dbx) run -c '[[ x1 == ~(E)\: ]]'
(dbx) print (char*)0xfffffd7fff0bd4f0
(char *) 18446741324914480368U = 0xfffffd7fff0bd4f0 "~(E):"
(dbx) run -c '[[ x1 == ~(E)\\: ]]'
(dbx) print (char*)0xfffffd7fff0bd4f0
(char *) 18446741324914480368U = 0xfffffd7fff0bd4f0 "~(E)\\:"
(dbx) run -c '[[ x1 == ~(E)\\\: ]]'
(dbx) print (char*)0xfffffd7fff0bd4f0
(char *) 18446741324914480368U = 0xfffffd7fff0bd4f0 "~(E)\\:"
Olga
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{ \/`o;====- Olga Kryzhanovska -====;o`\/ }
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/\/\ Solaris/BSD//C/C++ programmer /\/\
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