Re: DT in BGT
Interesting. So here's what I did. I created two new variables:
double T1 = cosine(theta);
double T2 = sine(theta);
Then, I told the ball to move, with a theta of 4.3. Logs showed that T1, or cosine(theta), was equal to 1. Sine(theta), was shown as 0. So next, instead of passing theta to move, I bypassed it, and simply changed theta manually to 4.3:
double theta = 4.3;
And now, the log has totally different values, and different cords: T1 is -0.400799172079975, and T2 is -0.916165936749455.
Ball is now at -0.014063128270208, -0.032146170735359, 499.803802490234.
So that means somehow theta isn't getting updated correctly. In other words, when I use:
void move(double theta)
And I say something like move(4.3), it's not actually updating it, even though the log says it is, or somehow it's not staying at that value. Is that correct?
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