Re: Pyglet help
Actually, just storing the full filename would probably work. So something like:
import os.path
import glob
types = [".mp3", ".wav", ".flac", ".mp4", ".mpg", ".avi", ".m4a"]
types = str(types)
playlist = []
path = input("Enter the path to your music folder.")
letter = input("Name of the song? ")
print(os.getcwd())
#list directories
with os.scandir(path) as it:
for entry in it:
if not entry.name.startswith('.') and entry.is_file():
name = os.path.splitext(str(os.path.split(entry)[1]))
if letter in name[0].lower():
if name[1].lower() in types:
playlist += [name[0]+name[1]]You could split the text again when displaying it if you don't want to list the extension, or shuffle the list to randomize playback.
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