on behalf of Andrew W
****** Forwarded Message Follows *******
--- Begin Message ---
Hello Anthony
(I can not submit to Aus-soaring but this might be interesting for the
group to know.)
A company overseas called "Jet RPM" already has retrofit jet
engines from 30 to 70 kg thrust for gliders for sale. The web site is;
http://www.jet-rpm.com/en/indexEn.htm
According to my calculations I will get 2 knots climb rate with a
22 kg jet. In Europe they give ASH25Ms a short car tow to get them
off the ground quickly on short strips and then they climb away on the
engine. I would be more than happy to take a winch or short autotow
and jet away with 30kg of thrust behind me.
I'm ready to become "Roger Ram Jet" anyday.
Regards
Andrew Wright
Date sent: Mon, 26 Mar 2007 11:35:42 +0950
From: Anthony Smith
<[EMAIL PROTECTED]>
Subject: RE: [Aus-soaring] Jets
To: David Lawley
<[EMAIL PROTECTED]>,
aus-soaring@lists.internode.on.net
Copies to: Send reply to:
[EMAIL PROTECTED],
"Discussion of issues relating to Soaring in
Australia."
<aus-soaring@lists.internode.on.net>
> >From a standing start the prop will probably get around
> 50-55kg thrust depending on engine and prop.
>
> As you get moving the props ability to produce thrust will
> start to reduce but the jet will keep on producing a
> relatively constant thrust.
>
> You will get to a speed where the jet will start producing
> more thrust and start to overtake the prop.
>
> Where the jests get an additional advantage is they are
> significantly lighter than the piston / prop combination
>
> > Far out guys!
> >
> > It sounds to me as though the only way to get an answer is
> > for me to get a LARGE spring balance scale, fixed firmly
> > to the ground and a rope attached to a glider with say
> > 60HP self launch, on a bitumen runway, go to full throttle
> > and see how hard it pulls, then do the same with a 25 kg
> > jet, as that will give a comparison of the actual standing
> > start power(But the prop type will need a spring balance
> > that measures to infinity, doesn't sound right to me
> > somehow)
> >
> > Well either that or go get a math's degree!
> >
> > Thank goodness I didn't ask for the complex answer!
> >
> > Dave
> >
> > -----Original Message-----
> > From: [EMAIL PROTECTED]
> > [mailto:[EMAIL PROTECTED] Sent: Monday, 26
> > March 2007 9:36 AM To: David Lawley
> > Subject: RE: [Aus-soaring] Jets
> >
> > For a prop aircraft:
> >
> > Thrust available = prop efficiency x power / speed.
> >
> > which so far doesn't make a lot of sense when speed = 0
> > because it makes the thrust available infinite.
> >
> > Prop efficiency largely depends on the prop adavance
> > ratio:
> >
> > Adv ratio = speed / (rpm x prop diameter)
> >
> > The prop has a polar curve in effect with peak efficiency
> > occuring at a particular advance ratio - hence you have
> > climb props and cruise props. The props are set to have
> > max propulsive efficiency at a particular advance ratio.
> >
> >
> > However at very low speeds we can say that the
> > realtionship between efficiency and advance ratio is
> > linear:
> >
> > Prop efficiency = k x advance ratio = k x speed / (rpm x
> > prop diameter)
> >
> > where k is the ratio between efficiency and advance ratio.
> > For a climb prop k may be around 1.43 or a little lower
> > depending on actual prop design.
> >
> > So thrust available is now:
> >
> > Thrust available = k x speed / (rpm x prop diameter) x
> > power / speed.
> >
> > The speed now cancels out
> >
> > Thrust available = k x power / (rpm x prop diameter)
> >
> > This is for low speed only. As you speed up k decreases.
> >
> >
> >
> > > Hi all,
> > >
> > > Let me rephrase the question, what is the conversion for
> > > thrust to horsepower assuming 0 airspeed, idea being
> > > what acceleration a jet powered glider will have from a
> > > standing start, ie takeoff?
> > >
> > > Regards
> > >
> > > Dave
> > >
> > > -----Original Message-----
> > > From: [EMAIL PROTECTED]
> > > [mailto:[EMAIL PROTECTED] On
> > > Behalf Of Anthony Smith
> > > Sent: Monday, 26 March 2007 7:50 AM
> > > To: 'Mike Cleaver'; 'Discussion of issues relating to
> > > Soaring in Australia.' Subject: RE: [Aus-soaring] Jets
> > >
> > > Actual Thrust = prop efficiency x power / speed.
> > >
> > > Working out the prop efficiency is the interesting bit.
> > >
> > > -----Original Message-----
> > > From: Mike Cleaver [mailto:[EMAIL PROTECTED]
> > > Sent: Sunday, 25 March 2007 10:32 PM
> > > To: [EMAIL PROTECTED]; Discussion of issues
> > > relating to Soaring in Australia.
> > > Subject: RE: [Aus-soaring] Jets
> > >
> > > At 21:36 25/03/2007, you wrote:
> > > >Yes, but it isn't straightforward, which is why people
> > > keep refering to >either thrust for jets and horses for
> > > props. >
> > > >It is probably easier to convert horsepower to thrust -
> > > but you will >need a chart of your propeller efficiency.
> > > >
> > > >
> > > >
> > > >-----Original Message-----
> > > > Anyone know the relationship between thrust and
> > > horsepower?
> > >
> > >
> > > The old Physics teacher in me (yes, me too!) says
> > > thrust = force
> > > work = force x distance
> > > speed = distance / time
> > > power = work / time = force x distance / time
> > > therefore power = thrust x speed
> > >
> > > with appropriate factors to convert from various units,
> > > but if you use the old imperial units then 1hp = 550
> > > ft-lbf/sec but then the aerodynamicists went and stuffed
> > > it all up by requiring the density of air to be
> > > expressed in slugs per cubic foot to make the imperial
> > > system work. (actually the error is using a pound as a
> > > force unit when it is really a mass unit - a slug is
> > > 32.2 lb mass!)
> > > Wombat
> > >
> > >
> > >
> > > >_______________________________________________
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> > >
> > >
> > >http://lists.internode.on.net/mailman/listinfo/aus-soarin
> > > g
> > > _______________________________________________
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> > >
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> _______________________________________________
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ANDREW WRIGHT
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