> check2 = check << 3;
> if (check2 < __val) {
> __val -= check2;
> k += 8;

it will take time more regularly than my algorithm. But there would be
cases that are worse and would be cases that are better. It must be
tested on the real AVR architecture :)
-- 

. ''`.                               Dmitry E. Oboukhov
: :’  :   email: [email protected] jabber://[email protected]
`. `~’              GPGKey: 1024D / F8E26537 2006-11-21
  `- 1B23 D4F8 8EC0 D902 0555  E438 AB8C 00CF F8E2 6537

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