I was thinking about using trigonometry in this way: I know that my camera has a vertical FOV in degrees, and I know the height of my cube. This way I can draw an isosceles triangle. Now I can use trigonometry. I divide the triangle in two horizontally and got two right triangles with these attributes: beta angle = FOV/2 b cathetus = cube.height / 2
in this way the distance from camera and the side of the cube is equal to the a cathetus so my formule should be: a = sin(beta) / b + cube.depth / 2 well... this idea of mine............... doesn't work in practice... I get a number way too far to what I achieved by trial and error =\ On 12 Nov, 17:40, Miroku <miroku...@yahoo.it> wrote: > Hi everyone, > I'm in a Flash Pro project with my View3D as big as the stage > and I'm trying to make a cube of the dimension of the stage which > would fit exactly the View. > Practically the user shouldn't be aware of the presence of a 3D cube > (unless I animate it) > > How can I achieve this? > > thank you in advance =)
