At 1241828865 time_t, Gregor Best wrote: > For example, is it really neccessary to swap with each visible client? > Wouldn't > swapping the client with the first slave client to the trick?
No, the purpose of the function is to put the client as the latest
slave, so this is the only way to do it.
But, if you move the array of ordered client to Lua, that'd be as simple
as:
local cl1idx, cl2idx
for k, v in ipairs(ordered_clients) do
if v == c1 then
cl1idx == k
elseif v == c2 then
cl2idx == k
end
if cl1idx and cl2 idx then break end
end
table.remove(ordered_clients, cl1idx)
table.remove(ordered_clients, cl2idx)
table.insert(ordered_clients, cl2idx, c1)
table.insert(ordered_clients, cl1idx, c2)
-- Call a hook for arranging the screen
No hook called, unless at the end. So that'd be a lot faster.
Cheers,
--
Julien Danjou
// ᐰ <jul...@danjou.info> http://julien.danjou.info
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// Ferns will rule the world.
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